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3 years ago

Carbon naturally occurs in two forms: diamond and graphite. Why do these two forms have very different properties?

1 answer:

8 0

The differences in the properties of diamond and graphite is as a result of how their particles are arranged in space. This space arrangement leads to distinct crystal structures for the two compounds. In diamond, the carbon atoms are arranged in tetrahedral shape while in graphite the carbon atoms arrayed in planes.

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Calculate the energy for vacancy formation in silver, given that the equilibrium number of vacancies at 800˚C (1073 K) is 3.6 ×

krek1111 [17]

Answer : The energy for vacancy formation in silver is, $1.762\times 10^{-19}J$

Explanation :

Formula used :

$N_v=N\times e^{(\frac{-E}{K\times T})}$

or,

$N=\frac{N_A\times \rho}{M}$

So,

$N_v=[\frac{N_A\times \rho}{M}]\times e^{(\frac{-E}{K\times T})}$

where,

$N_v$ = equilibrium number of vacancies = $3.6\times 10^{23}m^{-3}=3.6\times 10^{20}L^{-1}$

E = energy = ?

M = atomic weight = 107.9 g/mole

$N_A$ = Avogadro's number = $6.022\times 10^{23}mol^{-1}$

$\rho$ = density = $9.5g/cm^3=9.5g/ml=9500g/L$

T = temperature = $800^oC=273+800=1073K$

K = Boltzmann constant = $1.38\times 10^{-23}J/K$

Now put all the given values in the above formula, we get:

$3.6\times 10^{20}L^{-1}=[\frac{(6.022\times 10^{23}mol^{-1})\times 9500g/L}{107.9g/mol}]\times e^{[\frac{-E}{(1.38\times 10^{-23}J/K)\times 1073K}]}$

$E=1.762\times 10^{-19}J$

Therefore, the energy for vacancy formation in silver is, $1.762\times 10^{-19}J$

4 0

3 years ago

Read 2 more answers

What is the definition of relief in science terms

SOVA2 [1]

The apparent topography exhibited by minerals in thin section as a consequence of refractive index.

6 0

3 years ago

Consider the following data on some weak acids and weak bases:

Juli2301 [7.4K]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

8 0

3 years ago

Which of the following elements belong to the same pair?

butalik [34]

Answer:

B. Na and Li

Both are group I elements.

5 0

3 years ago

What is the specific heat capacity of an unknown metal if 75.00 g of the metal absorbs 418.6J of heat and the temperature rises

EleoNora [17]

Answer:

The specific heat capacity of the unknown metal is 0.223 $\frac{J}{g*C}$

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= 418.6 J
c= ?
m= 75 g
ΔT= 25 C

Replacing:

418.6 J= c* 75 g* 25 C

Solving:

$c=\frac{418.6 J}{75 g*25 C}$

c= 0.223 $\frac{J}{g*C}$

The specific heat capacity of the unknown metal is 0.223 $\frac{J}{g*C}$

3 0

2 years ago