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posledela
3 years ago
14

Carbon naturally occurs in two forms: diamond and graphite. Why do these two forms have very different properties?

Chemistry
1 answer:
kari74 [83]3 years ago
8 0
The differences in the properties of diamond and graphite is as a result of how their particles are arranged in space. This space arrangement leads to distinct crystal structures for the two compounds. In diamond, the carbon atoms are arranged in tetrahedral shape while in graphite the carbon atoms arrayed in planes.
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Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
4 years ago
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The boiling point of methanol is 64 7°C. Its melting point is -976°C. At room temperature (-25°C), methanol is in which state?
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At -25 °C, methanol, whose boiling point is 64.7 °C and its melting point is -97.6 °C, is in the liquid state.

The melting point is the temperature at which a substance passes from solid to liquid. Below the melting point, a substance is in the solid state. Above the melting point, a substance is in the liquid or gas state.

The boiling point is the temperature at which a substance passes from liquid to gas. Below the boiling point, a substance is solid or liquid. Above the boiling point, a substance is in the gas state.

At -25 °C, methanol is above the melting point (-97.6 °C) and below the boiling point (64.7 °C). Thus, it is in the liquid state.

At -25 °C, methanol, whose boiling point is 64.7 °C and its melting point is -97.6 °C, is in the liquid state.

You can learn more about the melting and boiling points here: brainly.com/question/5753603?referrer=searchResults

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What parts do all cells have?
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The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. Where would
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Answer:

The answer is B, Alanine would be in the interior and serine would be on the exterior of the globular protein.

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To further explain, the nature of solubility of side chain determines the position of the amino acid in the globular protein.

The hydrophilic amino acid such as serine are on the outside of the globular protein while the hydrophic amino acids such as leucine and alanine are on the interior of the globular protein.

This is why Alanine would be in the interior and serine would be on the exterior of the globular protein.

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