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3 years ago

What is 3x-2y=9 y=2x-7

2 answers:

7 0

Okay, these get easy with practice so don't post all of these online. First, substitute y in 3x-2y=9 for what it says y equals (2x-7). You now have: 3x-2(2x-7)=9. Breakdown:
3x-2(2x-7)=9
3x-4x+14=9
-1x=-5
x=5
next solve for y
y=2x-7
y=2(5)-7
y=10-7
y=3
And now we have x=5, and y=3.

NeX [460]3 years ago

5 0

Since you know that "y" is equivalent to "2x - 7" you can substitute that into the first equation

3x - 2y = 9
3x - [2(2x-7)]= 9
3x - (4x - 14) = 9
3x - 4x + 14 = 9
-x + 14 = 9
-x = -5
x = 5

y = 2x - 7
y = 2(5) - 7
y = 10 - 7
y = 3

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What is a number mulitplyed by 8 and added by 6?

HACTEHA [7]

Xy = 8
x + y = 6

x + y = 6
x - x + y = -x + 6
y = -x + 6

xy = 8
x(-x + 6) = 8
x(-x) + x(6) = 8
  -x² + 6x = 8
-x² + 6x - 8 = 0
-1(x²) - 1(-6x) - 1(8) = 0
-1(x² - 6x + 8) = 0
  -1 -1
  x² - 6x + 8 = 0
x² - 4x - 2x + 8 = 0
x(x) - x(4) - 2(x) + 2(4) = 0
x(x - 4) - 2(x - 4) = 0
(x - 2)(x - 4) = 0
  x - 2 = 0 or x - 4 = 0
+ 2 + 2   + 4 + 4
x = 2   or    x = 4

x + y = 6
2 + y = 6
- 2 - 2
y = 4
(x, y) = (2, 4)

or
x + y = 6
4 + y = 6
  - 4 - 4
y = 2
  (x, y) = (4, 2)

The two numbers that add up to 6 and multiply to 8 are 4 and 2.

8 0

3 years ago

Which statement best describes how to determine whether f(x) = x4 – x3 is an even function?

Setler79 [48]

It would equal x=0 so no

3 0

4 years ago

What is the 15th term in the pattern below? 1, 4, 9, 16, 25, 36, ...

Flura [38]

Answer:

(15×15)=225

Step-by-step explanation:

Following Terms:

(7×7)=49

(8×8)=64

(9×9)=81

(10×10)=100

(11×11)=121

(12×12)=144

(13×13)=169

(14×14)=196

(15×15)=225

Simple Pattern to follow.

6 0

3 years ago

Plz help me I need the answer ASAP

Sindrei [870]

You need to isolate 'y' so subtract 1 from both sides.

y < 5

8 0

3 years ago

Read 2 more answers

Determine the longest interval in which the given initialvalue problemis certainto have a unique twicedifferentiable solution. D

AlekseyPX

Answer:

t_o = 3, so solution exists on (0,4).

Step-by-step explanation:

Use Theorem

Divide equation with t(t — 4).

y''+[3/(t-4)]*y'+ [4/t(t-4)]*y=2/t(t-4)

p(t)=3/t-4—> continuous on (-∞, 4) and (4,∞)

q(t) = 4/t(t-4) —> continuous on (-∞,0), (0,4) and (4, ∞)

g(t) = 2/t(t-4)—> continuous on (-∞, 0), (0,4) and (4,∞)

t_o = 3, so solution exists on (0,4).

6 0

3 years ago