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3 years ago

"describe the equilibrium state of a reversible enzyme-catalyzed chemical reaction"

1 answer:

7 0

Answer is: the amount of substance of reactants and products of reaction do not change when chemical reaction is in chemical equilibrium.
In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which not change with time. Speed of direct and irreversible chemical reaction are equal.

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A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.029 M H C l , and the equivalence point is reached aft

Gnesinka [82]

Answer:

0.043 M

Explanation:

The reaction that takes place is:

Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

First we calculate how many HCl moles reacted, using the given concentration and volume required to reach the equivalence point:

0.029 M HCl * 37.3 mL = 1.0817 mmol HCl = 1.0817 mmol H⁺

As 1 mol of H⁺ reacts with 1 mol of OH⁻, in the 25.0 mL of the Ca(OH)₂ sample there are 1.0817 mmoles of OH⁻.

With that in mind we can calculate the hydroxide ion concentration in the original sample solution, using the calculated number of moles and given volume:

1.0817 mmol OH⁻ / 25.0 mL = 0.043 M

3 0

3 years ago

The balance of the following equations

myrzilka [38]

A. 6 NaOH + 2(NH4)3 PO4 -----> 2Na PO4 + 6H2O + 6NH3

b. C2 H6 O + 3O2 ----> 2CO2 + 3H2O

5 0

3 years ago

Write on the blanks the number of significant figures each number has.

Ilia_Sergeevich [38]

Answer:

43. 6 sig figs

44.6 sig figs

45. 2 sig figs

Explanation:

I used the Atlantic Pacific rule

P if decimal is present

A if decimal is absent

Pacific Ocean (number) Atlantic Ocean

7 0

3 years ago

What property of these items do cm or mm measure: length, volume, mass or temperature?

UNO [17]

Answer:

length

Explanation:

cm measures length. Think of a ruler.

7 0

3 years ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

7 0

3 years ago