13 An Ionic Bond
these are the characteristics of an ionic bond compounds like NaCl have these characteristics
14 substances could be compounds or elements hence not all substances are compounds
15 It is not water. The chemical composition of water is H2O not H202
(H202 is hydrogen peroxide and is toxic)
Answer:
The parts of an atom are electrons, usually found in an electron shell around the nucleus of the atom, and protons and neutrons, found in the nucleus of the atom. Typically, electrons are gained or lost in order to obtain charge.
<u>Answer: </u>
Phases of moon:
- New Moon
- crescent Moon
- First-quarter Moon
- gibbous Moon
- full Moon
<u>Explanation:</u>
The lunar cycle has 8 phases. The first phase is new moon. New moon is seen while the moon lies between the sun and the earth. After few days occurs the crescent moon when the moon travels towards its east. The next phase is first-quarter phase. During this phase half of the moon will be illuminated. The fourth phase is waxing gibbous moon phase where waxing refers to 'growing larger' and gibbous means 'shape' hence waxing gibbous refers to growing shape. Next is the full moon phase. This happens when the moon and the sun comes on the opposite sides of our earth. The next phase will be waning gibbous moon where the moon decreases in size. This phase is followed by third quarter and finally the waning crescent moon phase.
The balanced chemical equation for the <span>combustion of ethane is
2C</span>₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)
The stoichiometric ratio between C₂H₆(g) and CO₂(g) is 1 : 2
Hence,
moles of CO₂(g) produced = moles of reacted C₂H₆(g) x 2
= 1.00 mol x 2
= 2.00 mol
Hence, the correct answer is "C".
Answer:
<h3>The answer is 4.65 moles</h3>
Explanation:
To find the number of moles given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
N = 2.8 × 10²⁴ atoms of Cl2
So we have
We have the final answer as
<h3>4.65 moles</h3>
Hope this helps you
