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Dahasolnce [82]
3 years ago
7

Which is an example of a heterogeneous catalyst?

Chemistry
2 answers:
N76 [4]3 years ago
8 0
An example of a heterogeneous catalyst is a catalytic converter. A catalytic converter is an emissions control device that converts toxic pollutants in exhaust gas to less toxic pollutants by catalyzing a redox reaction (oxydation or reduction). 
g100num [7]3 years ago
5 0

Answer:

catalytic converter

Explanation:

A heterogeneous catalyst is one that has a phase different from the reactant molecules. A catalyst speeds up a chemical reaction by lowering the activation energy required to start the reaction. But a catalyst does not undergo any change in the chemical process. Catalysts in a catalytic converter are metallic palladium or platinum that react with the hydrocarbons and carbon monoxide from the exhausts of a car to form carbon dioxide and water.

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A full truckload of garbage has a mass of 26370 pounds . What is this mass in kilograms?
Likurg_2 [28]
  • The mass in kilograms is (11971.98 Kg)

  • Pounds can be  converted to pounds to kilograms by using this conversation (1 pound = 0.454 kilogram)

<em />

  • <em>Let X= mass of the object in kilograms</em>

  • <em>(1 pound = 0.454 kilogram)</em>
  • 26370 pounds = X kilograms

  • <em>If we cross multiply, we have </em>

  • (0.454 kilogram × 26370 pounds) = X kilograms

X = 11971.98 Kg

  • Therefore, mass in kilograms is  (11971.98 Kg)

Learn more   at : brainly.com/question/17482095

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3 years ago
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Explanation:

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2. A balloon full of air has a volume of 2.75 L at a temperature of 18°C. What is the balloon's volume
Sphinxa [80]

Answer:

3.01 L

Explanation:

V

1

: 2.75L

T

1

:  

18

∘

C

V

2

: ?

T

2

:  

45

∘

C

If you know your gas laws, you have to utilize a certain gas law called Charles' Law:

V

1

T

1

=

V

2

T

2

V

1

is the initial volume,  

T

1

is initial temperature,  

V

2

is final volume,  

T

2

is final temperature.

Remember to convert Celsius values to Kelvin whenever you are dealing with gas problems. This can be done by adding 273 to whatever value in Celsius you have.

Normally in these types of problems (gas law problems), you are given all the variables but one to solve. In this case, the full setup would look like this:

2.75

291

=

V

2

318

By cross multiplying, we have...

291

V

2

= 874.5

Dividing both sides by 291 to isolate  

V

2

, we get...

V

2

= 3.005...

In my school, we learnt that we use the Kelvin value in temperature to count significant figures, so in this case, the answer should have 3 sigfigs.

Therefore,  

V

2

= 3.01 L

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4 years ago
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