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hichkok12 [17]
3 years ago
14

En un supermercado tienen dos contadores eléctricos de flujo de personas 1 registra de 3 en 3 y el otro de 5 en 5 en el momento

que ambos se detienen unos señala de 840 y el otro de 560 diga Cuál de los dos es el que marca de 3 en 3?
Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0

Answer:

El contador que señala 840 registra de 3 en 3.

Step-by-step explanation:

Existe un truco para determinar si un número es múltiplo de 3, si la suma de sus dígitos es 3 o uno de sus múltiplos, entonces el número es un múltiplo de 3. En consecuencia, corresponde al contador eléctrico que registra de 3 en 3 y el otro contador eléctrico sería el que registra de 5 en 5.

Primer contador: 840

x = 8+4+0

x = 12

12 es un múltiplo de 3, por tanto, este contador es el que registra de 3 en 3.

Segundo contador: 560

x = 5+6+0

x = 11

11 no es un múltiplo de 3. Asimismo, todo número que sea múltiplo de 5 termina en 5 o 0, entonces este contador es el que registra de 5 en 5.

El contador que señala 840 registra de 3 en 3.

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posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\

Since\  \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0

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