Complete question:
Consider the hypothetical reaction 4A + 2B → C + 3D
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?
Answer:
the final concentration of A is 0.992 M.
Explanation:
Given;
time of reaction, t = 4.0 s
rate of change of the concentration of B = -0.0760 M/s
initial concentration of A = 1.600 M
⇒Determine the rate of change of the concentration of A.
From the given reaction: 4A + 2B → C + 3D
2 moles of B ---------------> 4 moles of A
-0.0760 M/s of B -----------> x

⇒Determine the change in concentration of A after 4s;
ΔA = -0.152 M/s x 4s
ΔA = -0.608 M
⇒ Determine the final concentration of A after 4s
A = A₀ + ΔA
A = 1.6 M + (-0.608 M)
A = 1.6 M - 0.608 M
A = 0.992 M
Therefore, the final concentration of A is 0.992 M.
Answer:
3.53*10^{-7} m
Explanation:
Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

Hence, we have

but the energy is also:

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

hope this helps!
Average velocity of man is 2 m/s
<u>Given that;</u>
Distance between tree and house = 16 m
Time taken = 8 seconds
<u>Find:</u>
Average<em> velocity</em>
<u>Computation:</u>
Average velocity = Total distance cover / Time taken
Average velocity = Distance between tree and house / Time taken
Average velocity = 16 / 8
Average velocity = 2 m/s
Learn more:
brainly.com/question/22610586?referrer=searchResults
Answer:
3m/s²
Explanation:
final velocity - initial velocity
______________________ = Acceleration
elapsed time