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Tanya [424]
2 years ago
13

________________________ energy is the energy that an object gets from its position and motion. Question 2 options: mechanical n

uclear electrical none of the above
Physics
1 answer:
shutvik [7]2 years ago
3 0
I think it’s kinetic
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If a bust starts to move and its velocity becomes 90 km after 8 seconds . calculate its acceleration answer it quick please
kherson [118]

Answer:

a = 3.125 [m/s^2]

Explanation:

In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.

90\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}   \\= 25 \frac{m}{s}

v_{f} =v_{i} + (a*t)

where:

Vf = final velocity = 25 [m/s]

Vi = initial velocity = 0

a = acceleration [m/s^2]

t  = time = 8 [s]

The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.

25 = 0 + a*8

a = 3.125 [m/s^2]

3 0
3 years ago
The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing
konstantin123 [22]

Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

5 0
2 years ago
Why does the closed top of a convertible bulge when the car is riding along a highway? Why does the closed top of a convertible
iren2701 [21]

Answer:

Option D

The air pressure inside the car is greater than the pressure outside.

Explanation:

When considering airflow over and around a surface, from Bernoulli's equation, air flow regions with higher velocity have a lower pressure, and regions with lower velocity have a higher pressure.

The air outside the convertible is moving faster than the air inside the convertible. This leads to a higher pressure zone just below the surface of the roof (inside the car) causing the roof of the convertible to bulge upwards

4 0
3 years ago
I need help please it’s for a lab
krok68 [10]

Answer:

idk

Explanation:

5 0
3 years ago
As a stands, her entire weight is momentarily placed on the heels of her high-heeled shoes. Calculate the pressure exerted on th
Lena [83]

Answer:

Pressure will be 6072449.952Pa

Explanation:

We have given mass of the women m = 65 kg

Radius of the heels r = 0.578 cm = 0.00578 m

We have to find the pressure

We know that pressure is given by

P=\frac{F}{A}=\frac{mg}{A}

So force F = mg = 65×9.8 = 637 N

Area A=\pi r^2=3.14\times 0.00578^2=1.049\times 10^{-4}m^2

So pressure p=\frac{637}{1.049\times 10^{-4}}=6072449.952Pa

5 0
3 years ago
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