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Tanya [424]
3 years ago
13

________________________ energy is the energy that an object gets from its position and motion. Question 2 options: mechanical n

uclear electrical none of the above
Physics
1 answer:
shutvik [7]3 years ago
3 0
I think it’s kinetic
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Un pendul cu arc oscileaza cu frecventa de 0,25Hz. Cite oscilatii efectueaza acest pendul timp de 10s?
vodka [1.7K]

Given:

The frequency of the pendulum ( f) = 0.25 Hz.

Total time (t) = 10 s

Concept: Frequency means, the number of oscillation in one second.

Time period is the required time by pendulum to complete one oscillation.

∵  In 1.0 second, number of oscillations = 0.25

∴ In 10.0 second, number of oscillations = (0.25 ×10.0) / 1.0 = 2.5

Hence, the required number of oscillation = 2.5  

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4 years ago
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3 years ago
The magnitudes of two forces are measured to be 120 ± 5 N and 60 ± 3 N. Find the sum and diff erence of the two magnitudes, givi
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Answer:

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3 years ago
A car starting from rest moves with a constant acceleration of 10 mi/hr2 for 1 hour, then decelerates at a constant 5 mi/hr2 unt
Vinvika [58]

Answer:

The total distance traveled by the car (S) = 15 mi

Explanation:

Total acceleration (a_{1}) = 10 mi / h^{2}

Time (t) = 1 hour

Deceleration (a_{2}) = - 5 mi / h^{2}

From law of speed we know that  V = u + a_{1} t -----------(1)

Where V = Final speed

           u = initial speed and t = time period

Car starts from rest so initial speed is zero so u = 0

Then equation 1 becomes V = a_{1} t = 10 × 1 = 10 mi / h ---------(2)

The distance traveled by the car S_{1} = u t + \frac{1}{2} × a_{1} × t^{2} -------------(3)

Put all the values in equation we get S_{1} = 0 + \frac{1}{2} × 10 × 1^{2}

                                                             S_{1} = 5 mi ---------------(4)

This is the distance traveled by the car in 1 hour.

In second case when car starts decelerates the equation of motion becomes

⇒ V = u - a t -----------(5)

final speed in this case = 0 and initial speed (u) = 10 mi / h

⇒ 0 = 10 - 5 t

⇒ 5 t = 10

⇒ t = 2 hours

Distance traveled by the car in to hours  S_{2} = u t + \frac{1}{2} × a_{2} × t^{2}

⇒ S_{2} = 10 × 2 - \frac{1}{2} × 5 × 2^{2}

⇒ S_{2} = 20 - 10

⇒ S_{2} = 10 mi

This is the distance traveled by the car in the next two hours.

Thus the total distance traveled by the car = S_{1} + S_{2}

⇒ S = 5 + 10 = 15 mi

3 0
3 years ago
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