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zaharov [31]
2 years ago
12

Which of the following best describes a coastal plain?

Physics
2 answers:
evablogger [386]2 years ago
5 0
Area near a sea having flat land and low relief
Katarina [22]2 years ago
4 0

<em>Hello,</em>

<em>The correct answer is....</em>

<em>B</em><em>) Area near a sea having flat land and low relief.</em>

<em>Hope this helps!!!! :)</em>

<em>**(</em><em>Vanessa</em><em>)**</em>

<em>**Can you please mark me Brainliest answer!!!!! Thanks!!!!! :)</em>

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The property that compares the mass of an object with its volume is _____.
Licemer1 [7]
The property that compares the mass of an object with its volume is density.
7 0
3 years ago
Read 2 more answers
Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe
Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * 10^{6} m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × 10^{-19} C

mass of electron  = 9.1 × 10^{-31} kg

Force in an electric field = q*E

potential energy is stored in the form of work done

potential energy = work done = Force * displacement

                                                   = q * (E * d)  

                                                   = q * (V) = 1.6 × 10^{-19} * 100

stored potential energy = kinetic energy in electric field

kinetic energy = 1/2 * m * v^{2}

                        = 1/2 *  9.1 × 10^{-31} *  v^{2}

equation both the equations

1/2 *  9.1 × 10^{-31} *  v^{2} = 1.6 × 10^{-17}

v^{2} = 0.352 * 10^{14} m/s

v^{2} = 35.2 * 10^{12}

    = 5.93 * 10^{6} m/s

To learn more about  kinetic energy in electric field  here

brainly.com/question/8666051

#SPJ4

3 0
1 year ago
Select the choice that best completes the following sentence. Simple machines A. reduce the amount of energy needed to do work.
boyakko [2]

It is actually are tools that make work easier C because i just had it on study island

7 0
3 years ago
Read 2 more answers
If a hydrogen atom has its electron in the n= 4 state, how much energy in eV is needed to ionize it?
ololo11 [35]

Answer:

Explanation:

Energy of electron in n = 4 state

= - 13.6/4² =- 0.85 eV

So energy needed to extract it from atom = .85 eV.

4 0
3 years ago
When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted p
jarptica [38.1K]

Answer:

1.76 eV

Explanation:

Maximum kinetic energy of the emitted photo electrons = energy of the photon- work function of the metal

K.E' = (hc/λ)-∅.................. Equation 1

Where K.E' = maximum kinetic energy of the emitted photo electrons, h = Planck's constant, c = speed, λ = wave length, ∅ = work function of the metal.

make ∅ the subject of the equation

∅ = (hc/λ)-K.E'.................. Equation 2

Given: h = 6.63×10⁻³⁴ J.s, c = 3×10⁸ m/s, λ = 400 nm = 400×10⁻⁹ m, K.E' = 1.1 eV = 1.1(1.602×10⁻¹⁹) J = 1.7622×10⁻¹⁹ J

Substitute into equation 2

∅ = [6.63×10⁻³⁴(3×10⁸)/400×10⁻⁹ ]-1.7622×10⁻¹⁹

∅ = (4.973×10⁻¹⁹)-(1.7622×10⁻¹⁹)

∅ = 3.21×10⁻¹⁹ J.

The maximum kinetic energy of the photo electrons when the wave length is 330 nm is

K.E' = [6.63×10⁻³⁴( 3×10⁸ )/330×10⁻⁹]-(3.21×10⁻¹⁹)

K.E' = (6.03×10⁻¹⁹)-(3.21×10⁻¹⁹)

K.E' = 2.82×10⁻¹⁹ J

K.E' = 2.82×10⁻¹⁹/1.602×10⁻¹⁹

K.E' = 1.76 eV

7 0
3 years ago
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