All categories

3 years ago

How many (whole number of) 91 kg people

2 answers:

6 0

We are given that the maximum mass capacity is 1 metric ton or 1000 kg. Therefore the amount of people this can hold is simply the ratio of the maximum mass capacity over the mass of the person, that is:

people = 1000 kg / 91 kg

people = 10.98

So the elevator can safely occupy 10 people. We will not exceed to 11.

Vesna [10]3 years ago

6 0

Answer:

<h2>10 people.</h2>

Explanation:

Gives

The elevator can hold a maximum weight of 1 metric ton.
1 metric ton is equivalen to 1000 kilograms, or which is the same $1.000 \times 10^{3} \ kg$ .
Each person weighs 91 kg.

To know the number of people that can safely occupy the elevator, we just need to divide

$\frac{1000 \ kg}{91 \ kg} \approx 10$

Therefore, around 10 people can safely occupy the elevator.

Notice that we can round the number to 11, because we cannot do that in real life with people. The decimal number is 10.98, but we there can't ve 10.98 people, because we can't have there a part of a person.

Therefore, the answer is 10 people.

You might be interested in

A hot-water bottle contains 787 g of water at 75∘C. If the liquid water cools to body temperature (37 ∘C), how many kilojoules o

IgorC [24]

Answer:

$Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal$

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

$29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ$

Explanation:

For this case we know the mass of the water given :

$m = 787 gr$

And we know that the initial temperature for this water is $T_i =75 C$ .

We want to cool this water to the human body temperature $T_f = 37 C$

Since the temperatures given are not near to 0C (fusion point) or 100C (the boling point) we don't need to use latent heat, then the only heat involved for this case is the sensible heat given by:

$Q= m c_p \Delta T$

Where $c_p$ represent the specific heat for the water and this value from tables we know that $c_p =1 \frac{cal}{gr C}$ for the water.

So then we have everything in order to replace into the formula of sensible heat and we got:

$Q = 787 gr * 1 \frac{cal}{gr C} *(37-75)C = -29906 cal$

So then the answer for this case would be 29906 cal but we need to convert this into KJ and we know that 1 cal = 4.184 J and if we convert we got:

$29906 cal *\frac{4.184 J}{1 cal}* \frac{1KJ}{1000 J}= 125.127 KJ$

8 0

3 years ago

Read 2 more answers

Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the

shutvik [7]

Period = 6 seconds and $frequency = 0.167Hz$ .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of $\frac{1}{t}$ . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency = $\frac{1}{t}$