1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gemiola [76]
3 years ago
15

How many (whole number of) 91 kg people

Physics
2 answers:
Tcecarenko [31]3 years ago
6 0

We are given that the maximum mass capacity is 1 metric ton or 1000 kg. Therefore the amount of people this can hold is simply the ratio of the maximum mass capacity over the mass of the person, that is:

people = 1000 kg / 91 kg

people = 10.98

 

So the elevator can safely occupy 10 people. We will not exceed to 11.

Vesna [10]3 years ago
6 0

Answer:

<h2>10 people.</h2>

Explanation:

Gives

  • The elevator can hold a maximum weight of 1 metric ton.
  • 1 metric ton is equivalen to 1000 kilograms, or which is the same 1.000 \times 10^{3} \ kg.
  • Each person weighs 91 kg.

To know the number of people that can safely occupy the elevator, we just need to divide

\frac{1000 \ kg}{91 \ kg} \approx 10

Therefore, around 10 people can safely occupy the elevator.

Notice that we can round the number to 11, because we cannot do that in real life with people. The decimal number is 10.98, but we there can't ve 10.98 people, because we can't have there a part of a person.

Therefore, the answer is 10 people.

You might be interested in
What is the momentum of and 200 kg car traveling south at 22 m/sec?
motikmotik
The momentum of the car is 4.4x10^3 kg•m/sec
5 0
3 years ago
Please help
JulsSmile [24]

Answer:

D

Explanation:

because it is the only one that has something to do with heat keyword would be boiling

7 0
3 years ago
A planetâs moon revolves around the planet with a period of 39 Earth days in an approximately circular orbit of radius of 4.8Ã10
Alchen [17]

Answer:

v = 895 m/s

Explanation:

Time period is given as 39 Earth Days

T = 39 days \times 24 hr \times 3600 s

T = 3369600 s

now the radius of the orbit is given as

r = 4.8 \times 10^8 m

so the total path length is given as

L = 2 \pi r

L = 2\pi (4.8 \times 10^8)

L = 3.015 \times 10^9

now the speed will be given as

v = \frac{L}{T}

v = \frac{3.015 \times 10^9}{3369600}

v = 895 m/s

7 0
3 years ago
As mentioned, electric fields are extremely interconnected with magnetic fields and these two types of force can travel together
Nady [450]

Answer: I think the answer is a wave/ a transverse wave, or electromagnetic waves as well.

4 0
3 years ago
Read 2 more answers
A 4 cm diameter ball is located 40 cm from a point source and 80 cm from a wall. What is the size of the shadow on the wall?
Slav-nsk [51]
<span>11.823 cm There is a slight ambiguity with this question in that I don't know if the measurements are from the surface of the ball, or the center of the ball. I will take this question literally and as such the point light source will be 124 cm from the wall. The key thing to remember is that ball won't be showing an effective diameter of 4 cm to the light source. Instead the shadow line is a tangent to the ball's surface. There is a right triangle where the hypotenuse is the distance from the center of the ball to the light source (42 cm), one leg of the triangle is the radius (2cm). That right triangle will define a chord that will be the effective diameter of the disk casting the shadow. The cosine of the half angle of the chord will be 2/42 = 1/21. The sine of the half angle then becomes sqrt(1-(1/21)^2) = sqrt(440/441) = 2sqrt(110) = 0.99886557. Now multiply that sine by 4 (radius of ball multiplied by 2 since it's the half angle and we want the full side of the chord) and we get an effective diameter of 3.995462279 cm. Now we need to calculate the effective distance that circle is from the wall. It will be slightly larger than 82 cm. The exact value will be 82 + cos(half angle) * radius. So 82 + 1/21 * 2 = 82 + 2/21 = 82.0952381 Now we have the following dimensions with a circle replacing the ball in the original problem. Distance from wall to effective circle = 82.0952381 cm Distance from effective circle to point source = 124 - 82.0952381 = 41.9047619 cm Effective diameter of circle = 3.995462279 cm And because the geometry makes similar triangles, the following ratio applies. 3.995462279/41.9047619 = X/124 Now solve for X 3.995462279/41.9047619 = X/124 124*3.995462279/41.9047619 = X 495.4373226/41.9047619 = X 11.82293611 = X The shadow cast on the wall will be a circle with a diameter of 11.823 cm</span>
7 0
3 years ago
Other questions:
  • Which observation BEST supports evidence that two different species share a common ancestor? A) they both prey on the same anima
    11·2 answers
  • A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ba
    14·1 answer
  • What factor determines an object's momentum?
    6·1 answer
  • What is the type of intermolecular force in methylated spirits
    15·1 answer
  • An incandescent bulb produces 520 lumens and has an efficacy of 13 lm/W.
    6·2 answers
  • If the voltage output of a digital manifold absolute pressure (MAP)sensor is 2 volts, the approximate engine vacuum is _______ i
    12·1 answer
  • WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!
    11·1 answer
  • What is a group of individuals of the same species living in the same geographic area
    15·1 answer
  • The effect of itching power what’s the Independent variable and dependent and constants?
    6·1 answer
  • An object that has momentum must have
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!