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Stolb23 [73]
3 years ago
10

How do I find applied force of an object given magnitude

Physics
1 answer:
Arte-miy333 [17]3 years ago
4 0
Google
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A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft, what is the mass (in kg) of water in the pool?
olga nikolaevna [1]

The mass (in kg) of water in the pool is 1.264 * $$10^6 kg.

<h3>What is mass?</h3>

A numerical measurement of inertia, a basic characteristic of all matter, in physics. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass. The kilogram serves as the SI's fundamental mass unit.

Given: A pool is 31.4 m long and 40.0 m wide. if the average depth of water is 3.30 ft

31.4 * 40.0 = 1256 $$m^2

1 m = 39.37 in = 3.28 ft

3.30 ft = 1.01 m

Volume of pool = 1256 * 1.01 = 1264 $$m^3

Since 1 $$m^3 water contains $$10^3$ kg the volume of the pool is

1.264 E3 * E3 = 1.264E6 kg

(or 1.264 * $$10^6 kg)

The mass (in kg) of water in the pool is 1.264 * $$10^6 kg.

To learn more about mass refer to:

brainly.com/question/19385703

#SPJ4

8 0
2 years ago
An elephant pushes with 2000 N on a load of trees. It then pushes these trees for 150 m. How much work did the elephant d
LiRa [457]

Answer:

300000

Explanation:

2000×150= 300000

6 0
3 years ago
Fees associated with buying and finalizing your loan are known as
-BARSIC- [3]

closing cost is the term to describe Fees associated with buying and finalizing your loan.

5 0
4 years ago
Which table is it I’ll mark brainlest
alexira [117]

Answer:

we need the graph to answer the question.

5 0
3 years ago
Calculate the Fermi energy and the conductivity at room temperature for germanium containing 5×10^16 arsenic atoms per cubic cen
Cloud [144]

Answer:

The Fermi energy is 0.568 eV and the conductivity at room temperature is 31.24 (Ωcm)⁻¹

Explanation:

Data given:

Nd = doping concentration = 5x10⁶/cm³

According the mass action law, the hole concentration is:

P_{0} =\frac{n_{i}^{2}  }{n_{0} } ,n_{i}=2x10^{13} /cm^{3}

E_{f} =E_{i} +KTln(\frac{n_{D} }{n_{i} } ),K=8.61x10^{-19} ,KT=0.026eV

E_{i} =\frac{E_{0} }{2} =\frac{0.63}{2} =0.315eV\\E_{f}=0.315+0.203=0.568eV

The conductivity of n-type of semi-conductor is equal to:

The mobility of Germanium is 3900 cm²/Vs

σ = 1.6x10⁻¹⁹ * 5x10¹⁶ * 3900 = 31.24 (Ωcm)⁻¹

6 0
3 years ago
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