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maks197457 [2]
2 years ago
14

You are an astronaut on a spacewalk to fix your spacecraft with a hammer. Your lifeline (tether) breaks and your jetpack on your

back is out of fuel. To return safely to your spacecraft (without anyone to help you) you should_______.
Physics
2 answers:
tamaranim1 [39]2 years ago
8 0

Explanation:

Here we will apply the law of conservation of momentum which is one of the powerful laws of physics. As this law states that the "if no external forces are acting on the system then the net momentum of the system before and after must remain conserved. As the astronaut has a hammer, if he throws it in the direction opposite of his space craft, he will automatically move towards the space craft to conserve the momentum. That's how he can reach the space craft easily by throwing away the hammer.

garri49 [273]2 years ago
3 0

Answer:

  • One must get rid of any heavy material like the jet pack and other materials other then the space suit. And, then as the amount of mass,m gained by the person decreases we know that there is a net gravitational force,F(G) between the spacecraft and the individual. So, the astronaut will be pulled by the larger in body spacecraft to itself and eventually will be saved due to the force of attraction present between the different celestial entities inside the universe.
  • So if i was one of the astronaut on a spacewalk to fix my spacecraft with a hammer. And lets say my lifeline (tether) breaks and my jet pack on my back is out of fuel. To return safely to my spacecraft (without anyone to help you) i should <u>first get rid of any heavy material other then my space suit and then i would myself will be compelled towards the space craft.</u>

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Un tren emplea cierto tiempo en recorrer 240 km. Si la velocidad hubiera sido 20 km por hora mas que la que llevaba hubiera tard
podryga [215]

Answer:

A train takes some time to travel 240 km. If the speed had been 20 km per hour more than the one it was carrying, it would have taken 2 hours less to travel this distance. In what time did he cover the 240 km

Explanation:

Given that,

A train travelled a distance of 240km

Let the initial speed be

S_1 = x km/hr

Let assume the time spent on the first journey is

t_1 = a

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Then, he would have take 2hrs less time

Then, time t_2 = a - 2

The common data fore the two journey is the distance

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For the first stage

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d = S_2 × t_2

d = (x+20) × (a - 2)

240 = (x+20) × (a - 2). Equation 2

Substitute equation 1 into 2

240 = (240/a + 20) × (a -2)

240 = 240 - 480/a + 20a - 40

240 - 240 + 40 = - 480/a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

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Divided through by 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

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(a-6)(a+4) = 0

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So, t_1 = a = 6hours,

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So, in the second journey the time use is 2hours less than the first journey

Then, t_2 = 6 - 2 = 4 hours

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t_2 = 4 hours

Spanish

Un tren recorrió una distancia de 240 km.

Deje que la velocidad inicial sea

S_1 = x km / h

Supongamos que el tiempo dedicado al primer viaje es

t_1 = a

Ahora si aumenta la velocidad a

S_2 = (x + 20) km / h

Entonces, habría tomado 2 horas menos de tiempo

Entonces, el tiempo t_2 = a - 2

Los datos comunes para los dos viajes son la distancia.

Velocidad = distancia / tiempo

Para la primera etapa

S_1 = d / t_1

d = S_1 × a

d = x × a

240 = x • a

x = 240 / a Ecuación 1

Para la etapa dos

d = S_2 × t_2

d = (x + 20) × (a - 2)

240 = (x + 20) × (a - 2). Ecuación 2

Sustituye la ecuación 1 en 2

240 = (240 / a + 20) × (a -2)

240 = 240 - 480 / a + 20a - 40

240 - 240 + 40 = - 480 / a + 20a

240 - 240 + 40 = (-480 + 20a²) / a

40 = (-480 + 20a²) / a

40a = -480 + 20a²

20a² - 40a -480 = 0

Dividido entre 20

a² - 2a - 24 = 0

a² + 4a - 6a - 24 = 0

a (a + 4) -6 (a + 4) = 0

(a-6) (a + 4) = 0

(a-6) = 0 o (a + 4) = 0

Entonces, a = 6 o a = -4

El tiempo no puede ser negativo, entonces, el tiempo es a = 6 horas

Entonces, t_1 = a = 6 horas,

Entonces, el tiempo utilizado en el primer viaje es de 6 horas

Entonces, en el segundo viaje, el uso del tiempo es 2 horas menos que el primer viaje

Entonces, t_2 = 6 - 2 = 4 horas

t_1 = 6 horas

t_2 = 4 horas

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