I believe the work input= Fi × di. Work input is work done on a machine equal to the effort force times the distance through which the force is applied. On the other hand the work output is the work that is done by a machine equals resistance force times the distance through which the force is applied.
Answer:
ΔV=0.00043 L
Explanation:
Given that
V= 0.3 L
T= 14 °C
T'=27°C
Coefficient of volume expansion




ΔV=0.00043 L
Answer:
7800 J
Explanation:
Heat needed = mass of copper x specific heat of copper x change in temperature
Change in temperature = 30ºC - 20ºC = 10ºC
Specific heat of copper = 390 J/kgºC
Mass of copper = 2 Kg
Substituting the given values in above equation, we get –
Heat needed = 2 Kg x 390 J/kgºC x 10ºC
= 7800 J