Answer:
Explanation:
During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s 
v = u + at 
1.2 = 0 +  .8 a 
a = 1.2 / .8 
= 1.5 m /s²
During the acceleration in upward direction , let reaction force of ground on man be R . 
Net force on man = R - mg 
Applying Newton's 2 nd law 
R - mg = ma 
R = m ( g + a ) 
= 72 ( 9.8 + 1.5 ) 
= 813.6 N . 
This reaction force will be measured by spring scale , so reading of spring scale will be 813.6 N . 
 
        
             
        
        
        
Answer:

Explanation:
From the question we are told that: 
Crane Length 
Crane Mass 
Arm extension at lifting end 
Arm extension at counter weight end 
Load 
Generally the equation for Torque Balance is mathematically given by



 
        
             
        
        
        
Answer:
The diagram assigned B
explanation:
Check the direction of the two vectors, their resultant must be in the same direction.
 
        
             
        
        
        
If one of two interacting charges is doubled, the force between the charges will  double.
Explanation:
The force between two charges is given by Coulomb's law 
 
 K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
 F'= 2 F
Thus the force gets doubled.
 
        
             
        
        
        
Answer:
 in the parallel connection the light bulbs shine less than in the series connection
Explanation:
In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is
            P = i² R
where R is the resistance of each bulb and i the current of the circuit.
If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,
             i = i₁ + i₂
if the two light bulbs are the same
            i = 2 i₁
            i₁ = i / 2
so the power of each bulb is is
            P = i₁² R
            P = R i² / 4
            P = ¼ P_initial
 Therefore we see that in the parallel connection the light bulbs shine less than in the series connection