This is how you would do it. set up the rxn. balance, in this case you didn't need to. make a grid and cancel out units.
Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g
.90 dL is 90 mL because 1 dL is 100 mL
Answer:
D.
Explanation:
Only 0.0035% of the electromagnetic spectrum is visible to the human eye
Hopefully this helped :)
Answer: Well "ordinary ice" is made from water (as we all know) and dried ice is made from carbon dioxide gas
Explanation:
•Hope this helps•
