$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$450\\ r=rate\to 6.5\%\to \frac{6.5}{100}\dotfill &0.065\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years \end{cases}$

$\bf A=450\left(1+\frac{0.065}{1}\right)^{1\cdot t}\implies \underset{\textit{growth factor}}{A=450(\underset{\uparrow }{1.065})^t}$

8 0

4 years ago

The functions f(x) = (x + 1)2 − 2 and g(x) = -(x − 2)2 + 1 have been rewritten using the completing-the-square method. Is the ve

Ksenya-84 [330]

Answer:

The negative outside the parentheses indicates that the vertex is a maximum

f(x) has a minimum vertex

g(x) has a maximum

Step-by-step explanation:

7 0

3 years ago

Find the highest common factor (HCF) of 270 and 450.

lbvjy [14]

Answer:

HCF = 90

Step-by-step explanation:

Hope it Helps!!!

3 0

2 years ago

a winery has a vat with two pipes leading to it. the inlet pipe can fill the vat 7 hours, while the outlet pipe can empty it in

raketka [301]

Lets say, for ease, that the vat can hold a total of 70 gallons (or whatever you would like to use.) Use whatever number you want, I just picked this because it gives us a lot of clean numbers.

Now, if the inlet can fill it in 7 hours, that means that it is adding 10 gallons per hour. (70 gal/7 hours = 10 gal/hr)

For the outlet, use the same process, and you find that it drains the vat at 7 gallons per hour.

So, if you subtract the outlet from the inlet, you get 10 - 7 = 3 gallons per hour added.

Now just divide the size of the vat by that number, and you find your answer.

70 gallons / 3 gallons per hour = 23 1/3 hours.

6 0

3 years ago