14 over 21 simplified

Mathematics

2 answers:

Romashka [77]3 years ago

5 0

2/3 because you can divide 7 into both and it will work....

anastassius [24]3 years ago

4 0

2 over 3 is 14 over 21 simplified, dividing both numbers by 7.

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Solve the following system of equations:<br><br> x − 2y = 14<br> x + 3y = 9

nikdorinn [45]

(12,-1) or x=12 and y=-1

EXPLANATION:
you set both equations equal to each other by subtracting the sum and adding it to the equation. once you set them equal to eachother (x-2y-14=x+3y-9)
you can solve by moving everything to one side by subtracting. once you get it all to one side you can start adding common numbers and variables and solve

6 0

3 years ago

Read 2 more answers

HELP I NEED THE ANSWERS FOR ALL OF THESE QUESTIONS!

inysia [295]

11. 38*
14. 1808,64m3
13. 5/3ft
i cant figure out the two left

7 0

3 years ago

IB QUESTIONS:

enyata [817]

Step-by-step explanation:

Using SOHCAHTOA

$\tan = \frac{opposite}{adjacent} \\ \tan {31}^{0} = \frac{450}{x} \\ \tan {31}^{0} = 0.6009 \\ 0.6009 = \frac{450}{x} \\ cross \: multiply \\ 0.6009x = 450 \\ divide \: both \: sides \: by \: 0.6009 \\ x = \frac{450}{0.6009}x \\ = 748.9$

Second Question Explanation:

a. The base angles of an isosceles triangle are equal so angle ABC is also 32°

but the sum of angles in a triangle = 180° therefore

let angle CAB be x

${32}^{0} + {32}^{0} + {x}^{0} = {180}^{0} \\ 64 + x = 180 \\ {x}^{0} = 180 - 64 \\ {x}^{0} = {116}^{0}$

b. If you share a triangle in half you get 2 right angles so I'll use SOHCAHTOA to find the length AB

First the base of the right angled triangle will be 20/2 = 10

$\cos = \frac{adjacent}{hypotenuse} \\ \cos {32}^{0} = \frac{10}{ab} \\ \cos32 = 0.8480 \\ 0.8480 = \frac{10}{ab} \\ ab = \frac{10}{0.8480} \\ line \: ab = 11.8$

c. To find the are we'll need to get the height first

using the right angled triangle With base 10cm and hypotenuse 11. 8 to find the height we'll use the Pythagorean theorem

${(11.8)}^{2} = {x}^{2} + {10}^{2} \\ 1324.24 = {x}^{2} + 100 \\ {x}^{2} = 139.24 - 100 \\ {x}^{2} = 39.24 \\ \sqrt{ {x}^{2} } = \sqrt{39.24} \\ x = \sqrt{39.24 } \\ x = 6.3$

now to find the area

$area \: of \: triangle = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 20 \times 6.3 \\ \frac{20 \times 6.3}{2} \\ = \frac{126}{2} \\ 63 {cm}^{2}$