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Mariulka [41]
4 years ago
6

Four point charges, each of magnitude 12.6 µC, are placed at the corners of a square 92.7 cm on a side. If three of the charges

are positive and one is negative, find the magnitude of the force experienced by the negative charge. The value of Coulomb’s constant is 8.98755 × 109 N · m2 /C 2 . Answer in units of N
Physics
1 answer:
mel-nik [20]4 years ago
5 0

Explanation:

F is the electric force K is the coulomb,s constant equal to 8.98755x10 9N .m2/C 2 Q'anf Q2 are two charges d is the distance between two charges First, let's compute the force between the two positive charges denotes as F1. F1=(8.98755×10 N.m2/C2)(+53×10×10-6 C)/35cm *1m/100cm)2 F 1=206.09 N

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Answer:

The magnitude of force on P is 2.75 N

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Acceleration when the forces are in opposite direction, a' = 0.400 m/s^{2}

Now,

The net force on the object in first case is given by:

F_{net} = |\vec{F_{P}}| + |\vec{F_{Q}}| = Ma       (1)

The net force on the object in second case is given by:

F_{net} = |\vec{F_{P}}| - |\vec{F_{Q}}| = Ma'       (2)

Adding both eqn (1) and (2):

2|\vec{F_{Q}}| = M(a + a')

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