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Kazeer [188]
3 years ago
8

Which postmortem parameter is fixed by 8 hours?

Chemistry
1 answer:
lara [203]3 years ago
4 0

Answer:

Algor mortis is the change which is an immediately sign of death. It involves the cooling of body. The body temperature decreases as the body after death looses the control over the circulation and exchange of gases and the control over the homeostasis. The temperature decreases until the body attains equilibrium with the external environmental temperature. The postmortem cooling or algor mortis gets fixed by 8- 10 hours after death. The temperature of the body after death can be used to determine the time since death. This can be measured by determining the temperature of the rectum which is proved to be most accurate or any other orifice such as nasal, ear and vaginal can also be used.

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When 1 mol of a fuel burns at constant pressure, it exchanges-3452 kJ of heat and does-11 kJ of workon the surroundings. What ar
Degger [83]

Answer:-3463 kJ and -3452kJ

Explanation:

ΔU is the change in internal energy of a system and its formula is;

ΔU = q + w

Where q represents heat transferred into or out of the system. Its value is positive when heat is transfer into the system and negative when heat is produced by the system.

W represents the work done on or by the system. Its value is positive when work is done on the system and negative when it is done by the system.

For the system in this question, we see that it produces heat which means heat is transferred out of the system, therefore the value of q is negative, it can also be seen that work is done by the system which means that w is also negative.

Therefore,

ΔU = -q-w

ΔU = -3452 kJ – 11kJ

= - 3463kJ

ΔH is the change in the enthalpy of a system and its formuls is;

ΔH = ΔU + Δ(PV)

By product rule Δ(PV) becomes ΔPV + PΔV

At constant pressure ΔP = 0. Therefore,

ΔH = -q-w + PΔV

w is equals to PΔV, So:

ΔH = -q

ΔH = -3452kJ

6 0
3 years ago
How many grams of solute are needed to make 2.50 L of a 1.75 M solution of Ba(NO3)2?
Eddi Din [679]

1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2. Details about molarity can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles can be calculated by using the following formula:

Molarity = no of moles ÷ volume

no of moles = 1.75 × 2.5

no of moles = 4.38mol

molar mass of Ba(NO3)2 = 261.34g/mol

mass of Ba(NO3)2 = 261.34 × 4.38

mass of Ba(NO3)2 = 1143.4grams.

Therefore, 1143.4grams of solute are needed to make 2.50L of a 1.75M solution of Ba(NO3)2.

Learn more about mass at: brainly.com/question/19694949

3 0
2 years ago
If one mole of PtCl2·3NH3 reacts with AgNO3 to produce one mole of AgCl(s), how can the formula PtCl2·3NH3 be re-written to show
Tresset [83]
The correct answer is b) [Pt(NH₃)₃Cl]Cl
Due to:
Chloride ion which is present outside the co-ordination sphere will react with AgNO₃ & since the reaction produces only one mole of AgCl so one Cl only outside the sphere and the formula is: [Pt(NH₃)₃Cl]Cl<span />
4 0
3 years ago
Please Help 3. Were there any metallic compounds that did not react with either the acid or the base? Write the type of metal, b
Norma-Jean [14]

Answer:

1)KNO3 ( pottasium trioxonitrate (V)

2)Ca(NO3)2 (calcium trioxonitrate (V

Explanation:

1)KNO3 ( pottasium trioxonitrate (V)

2)Ca(NO3)2 (calcium trioxonitrate (V)

Thses two compounds are metallic compounds and does not react with either the acid or the base.

Write the type of metal, based on your examination of the periodic table?

1)KNO3 ( pottasium trioxonitrate (V) have a potassium element which belongs to group 2 of the Periodic table which is an alkaline metal and can react with water or steàm

2)Ca(NO3)2 (calcium trioxonitrate (V) has calcium metal element which is an alkaline earth metal in the Periodic table and they react with Hallogens

5 0
3 years ago
Calculate the molar solubility of PbBr2 (Ksp = 4.67x10-6) in 0.10M NaBr solution.
Softa [21]

Explanation:

PbBr_{2} will dissociate into ions as follows.

         PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)

Hence, K_{sp} for this reaction will be as follows.

                   K_{sp} = [Pb^{2+}][Br^{-}]^{2}

We take x as the molar solubility of PbBr_{2} when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

               [Pb^{2+}] = [Pb^{2+}]_{o} + x

               [Br^{-}]^{2} = [Br^{-}]_{o} + 2x

So, equilibrium solubility expression will be as follows.

            K_{sp} = ([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains [Br^{-}]_{o} = 0.10 and there will be no lead ions. So, [Pb^{2+}]_{o} = 0

So, [Br^{-}]_{o} + 2x will approximately equals to [Br^{-}]_{o}.

Hence, K_{sp} = x[Br^{-}]^{2}_{o}

            4.67 \times 10^{-6} = x \times (0.10)^{2}

                        x = 4.67 \times 10^{-4} M

Thus, we can conclude that molar solubility of PbBr_{2} is 4.67 \times 10^{-4} M.

5 0
3 years ago
Read 2 more answers
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