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marshall27 [118]
2 years ago
8

CAN SOMEOME GIVE ME AN EXAMPLE OF

Chemistry
1 answer:
n200080 [17]2 years ago
7 0

Answer:

- A ball does not move unlesss you kick it and it rolls aways

- a car stays still and is not in motion, unless you start the engine

- a pencil stays still on a table, it moves when you pick it up off the table

Explanation:

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Which temperature in Celsius (°C) does this thermometer show? –8° 0° 25° 32°
natka813 [3]

Answer:

0° Celsius

Explanation:

The thermometer shows 0° Celsius which corresponds to 32° F.

3 0
3 years ago
4. Explain how radioactive isotopes are used to detect health problems.
drek231 [11]
Radioisotopes are widely used to diagnose disease and as effective treatment tools. For diagnosis, the isotope is administered and then located in the body using a scanner of some sort.
6 0
3 years ago
Un lote de 250 pijamas tiene un de 20.000, ¿cuál es el costo de cada pijama?<br>​
zysi [14]
Answer in file below

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6 0
3 years ago
The metal element cesium has one electron in its outer orbit. Will cesium atoms form positively charged or negatively charged io
r-ruslan [8.4K]

Answer:

Caesium atoms will form positively charged ions.

Explanation:

Due to them having one electron in their outer orbit, it is very likely that they will give that electron away to form an octet and become stable. Hence, since they lose an electron, they lose a negative charge, and in comparison to their former non-ion self, they have gained a positive charge.

Hence, they will form positively charged ions.

Hope this helped!

8 0
3 years ago
If 5.12 g of oxygen O2 gas occupies a volume of 6.21L at a certain temperature and pressure, how many grams of oxygen gas will o
ddd [48]

Answer : The mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

Explanation :

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}=\frac{5.12g}{32g/mol}=0.16mol

Now we have to calculate the moles of O_2 in 30.3 L by using Avogadro's law.

Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

V\propto n

or,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1 = initial volume of gas = 6.21 L

V_2 = final volume of gas = 30.3 L

n_1 = initial moles of gas = 0.16 mol

n_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{6.21L}{0.16mol}=\frac{30.3L}{n_2}

n_2=0.781mol

Now we have to calculate the mass of O_2

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

Molar mass of O_2 = 32 g/mol

\text{ Mass of }O_2=(0.781moles)\times (32g/mole)=24.9g

Therefore, the mass of O_2 occupy 30.3 L under the same conditions will be, 24.9 grams.

6 0
3 years ago
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