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Agata [3.3K]
3 years ago
5

Consider this equilibrium:

Chemistry
1 answer:
makvit [3.9K]3 years ago
7 0

Answer:

It remains constant as the concentration of products remains constant.

Explanation:

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When you are balancing chemical reactions ('equations'), what must you never touch?
timofeeve [1]

You should never touch the subscripts, as that will change the composition. Hope I helped!

8 0
3 years ago
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Which is NOT a control in the following experiment?: An experiment was performed to determine how the amount of coffee grounds c
Alexandra [31]

Answer:

The same kind of coffee, the same coffee maker, the same amount and type of water, and the same electrical sources were used.

Explanation:

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3 years ago
Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. what is the word equation for
melisa1 [442]
When magnesium is burned, it reacts with oxygen in air not with the fire. The fire is the energy needed for the reaction to happen. Magnesium reacts with oxygen forming magnesium oxide. The light emitted from the reaction is because the reaction produced a lot of heat.
6 0
3 years ago
Here is the electron configuration for Magnesium. How many total electrons are in the 2nd energy level?
balandron [24]

Answer:

8 electrons

Explanation:

Magnesium is present on group 2.

It has 2 valence electrons.

Electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

1st energy level contain 2 electrons.(1s²)

2nd energy  level contain 8 electrons. (2s² 2p⁶)

3rd energy level contain 2 electrons. (3s²)

3rs energy level of magnesium is called valence shell. It contain two valance electrons. Magnesium can easily donate its two valance electrons and get stable electronic configuration.

It react with halogens and form salt. For example,

Mg + Cl₂   →   MgCl₂

7 0
3 years ago
For the reaction 2 s (s) + 3 o2 (g) → 2 so3 (g), how much so3 can be produced from 4 g o2 and excess s? 1. 0.25 mol so3 2. 0.13
igor_vitrenko [27]
The balanced equation for the above reaction is as follows;
2S + 3O₂ --> 2SO₃
Stoichiometry of O₂ to SO₃ is 3:2
O₂ is the limiting reactant and S is provided in excess. since O₂ is the limiting reactant, the whole amount is consumed in the reaction and amount of product formed depends on amount of limiting reactant present.
Number of O₂ moles reacted- 4 g / 32 g/mol = 0.125 mol
3 mol of O₂ forms 2 mol of SO₃
therefore when 0.125 mol of O₂ reacts number of SO₃ moles - 2/3 x 0.125 mol
Number of SO₃ moles formed - 0.0833 mol
Answer is 4) 0.08 mol
8 0
3 years ago
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