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densk [106]
2 years ago
15

What happens when nitrogen and hydrogen comes in contact at high temperature and pressure in presence of iron powder and molybde

num
Chemistry
1 answer:
Sidana [21]2 years ago
6 0

Answer:

<h2>Ammonia Gas</h2>

Explanation:

It result in formation of ammonia gas.

N2 + 3H2 ---<u>iron</u><u>/</u><u>molybdenum</u><u>/</u><u>high</u><u> </u>temp/pres--- > 2 NH3

It forms ammonia gas.

Please mark branliest if you are satisfied with the answer. Thanking in anticipation.

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What is the pH for a 0.10 M HCI solution at 25<br> degreesCelsius?
11Alexandr11 [23.1K]

Answer:

1.0

Explanation:

Hydrochloric acid is a strong acid, that is, an acid that dissociates completely, according to the following reaction.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

Then, the concentration of H⁺ will be equal to the initial concentration of the acid, i.e., 0.10 M.

We can calculate the pH using the following expression.

pH = -log [H⁺] = -log 0.10 = 1.0

3 0
3 years ago
Consider the following data:
VikaD [51]

∆H ° rxn =-2855.56 kJ

<h3>Further explanation</h3>

Given

ΔHf CO₂ = -393.5 kJ/mol

ΔHf H₂O = -241.82 kJ/mol

ΔHf  C₂H₆ = - 84.68 kJ/mol

Reaction

2C2H6(g) + 7O2(g) -> 4CO2(g) + 6H2O(g)

Required

ΔHrxn=

Solution

<em>∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants) </em>

∆H ° rxn = (4.-393.5+6.-241.82)-(2.-84.68)

∆H ° rxn = (-1574-1450.92)-(-169.36)

∆H ° rxn =-3024.92+169.36

∆H ° rxn =-2855.56 kJ

8 0
3 years ago
Read 2 more answers
Living organisms make their own carbon
san4es73 [151]
Where’s the question is this a true or false question
3 0
3 years ago
A gas exerts a pressure of 4.1 atm at 300K. What is the pressure of the gas at 1010K?
Ainat [17]

Answer: 10

Explanation: 10 + 4.1 = 10

7 0
2 years ago
Perform the following mathematical operation and express the results to the correct number of significant figures. (0.102 x 0.08
Kobotan [32]

Answer:

<u>2.26 </u>

<u></u>

Explanation:

First you should know what are significant figures,

1 . All non - zero digits are significant.

2 . The zero between two non-  zero are significant.Ex 302 has 3 significant figures.

3. The zero before the decimal and before any non-zero digit is non significant. Example : 0.003 has only 1 significant figure.

4. The zero after non zero are non - significant . But the zeros after the decimal point are significant.

300 has only 1 significant figure

300.0 has 4 significant figure

The least number of significant figures present in the number should be there in the final answer of the calculation.

Look at the number having minimum significant digits :

It is 3 (every number has 3- significant figures ) So the answer should also contain 3 - significant figures.

\frac{0.102\times 0.0821\times 273}{1.01}

First solve the numerator part

\frac{2.285}{1.01}

=2.2635

Round off this number to 3 significant figures.

Answer is =<u> 2.26</u>

It has 3 - significant digit since all the digits are non-zero.

5 0
2 years ago
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