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3 years ago

What is the volume occupied by 2.50 moles of oxygen gas at STP

1 answer:

8 0

1 mole of any gas under STP has volume 22.4 L
So 2.50 moles of any gas ( including oxygen)
2.50 mol *(22.4L/1 mol)=56.0 L

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The positively charged particles in an atoms nucleus is the A electron. B neutron. C proton. D isotope.

Mama L [17]

Answer:

Proton

Explanation:

3 0

3 years ago

According to the periodic table, carbon has an atomic mass of 12.011 u. This indicates that the most abundant isotope of carbon

Eduardwww [97]

The most abundant of all of the isotopes of an element will be the one who's mass the mass of element is closest to. In this case, the mass of atomic carbon is closest to the mass of carbon-12.
Thus, Carbon-12 is the most abundant isotope.

3 0

3 years ago

Read 2 more answers

a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0

3 years ago

What is the mass in grams of 5.2 moles of NaCl?<br> 303.89 g<br> 0.09 g<br> 119.6 g<br> 1828

Vitek1552 [10]

Explanation:

mole=mass/molar mass

mass= mole×molar mass

m= 5.2×( 23+35.5)

m= 5.2×58.5

m= 304.2g

6 0

3 years ago

This is the answer fellas

lubasha [3.4K]

Answer:

Thx man!

Explanation:

Brainliest Please!

5 0

3 years ago