Answer:
600 m is required for smaller plane to reach its takeoff speed.
Explanation:
We have equation of motion
80 = 0 + a x 30
a = 2.67 m/s²
Now finding distance traveled by second flight
v² = u²+2as
40² = 0²+2 x 2.67 x s
s = 300 m
So 300 m is required for smaller plane to reach its takeoff speed.
Answer:
45C in a minute is
45/60 C in a second
.75 C in a second is 3/4 of an ampere.
Explanation:
The strain energy stored in a linear spring is
SE = (1/2)*k*x²
where
k = the spring constant
x = the extension (or compression) of the spring
Given:
k = 470 N/m
x = 17.0 cm = 0.17 m
Therefore
SE = 0.5*(470 N/m)*(0.17 m)² = 6.7915 J
Answer: 6.8 J (nearest tenth)
Yes it is consider biology