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n200080 [17]
3 years ago
13

You apply the brakes of your car abruptly and your book starts sliding off the front seat. Three observers sitting in the car ex

plain this differently. Observer A says that the book continued moving and the car accelerated from underneath it. Observer B says that the car pushed forward on the book. Observer C says that she must be in a noninertial reference frame because the book started moving without any extra objects interacting with it. Which of the observers is correct? Assume that the car is a frame of reference of all observers.
Physics
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

All the observers are correct.

Explanation:

This is simply a problem of reference frames from which the motion of the book is being viewed by the various observers.

From their various reference frames, they are all correct.

Observer A must be in the inertial reference frame.

<em>Observers who can explain the behavior of the book  and the car by using the relationship between the sum of  the forces and changing velocity are said to be observers in inertial reference frames.</em>

This is clearly shown by what observer A noticed. There was a relative motion between the book and the car as she pointed out, making her to be in an inertial reference frame.

<em>Similarly, observers in inertial reference frames can also explain the changes in velocity of objects  by considering the forces exerted on them by other objects.</em>

This is shown by observer B as he is able to notice how the force of the car affects the velocity of the book.

Observer C is actually in a non-inertial reference frame, as newtons law of force motion relationship are no longer observed. This occurs in the non inertial reference frame.

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In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance
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Answer:

Capacitive Reactance is 4 times of resistance

Solution:

As per the question:

R = X_{L} = j\omega L = 2\pi fL

where

R = resistance

X_{L} = Inductive Reactance

f = fixed frequency

Now,

For a parallel plate capacitor, capacitance, C:

C = \frac{\epsilon_{o}A}{x}

where

x = separation between the parallel plates

Thus

C ∝ \frac{1}{x}

Now, if the distance reduces to one-third:

Capacitance becomes 3 times of the initial capacitace, i.e., x' = 3x, then C' = 3C and hence Current, I becomes 3I.

Also,

Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}

Also,

Z ∝ I

Therefore,

\frac{Z}{I} = \frac{Z'}{I'}

\frac{\sqrt{R^{2} + (R - X_{C})^{2}}}{3I} = \frac{\sqrt{R^{2} + (R - \frac{X_{C}}{3})^{2}}}{I}

{R^{2} + (R - X_{C})^{2}} = 9({R^{2} + (R - \frac{X_{C}}{3})^{2}})

{R^{2} + R^{2} + X_{C}^{2} - 2RX_{C} = 9({R^{2} + R^{2} + \frac{X_{C}^{2}}{9} - 2RX_{C})

Solving the above eqn:

X_{C} = 4R

6 0
3 years ago
A man travels 25 kilometers in 15 minutes. A police officer stops him and
andreev551 [17]

Answer:

yes

Explanation:

cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour

15=25

15x4=60 25x4=100

so yes

he was going 100km per hour

6 0
3 years ago
An alien spaceship traveling at 0.600c toward the Earth launches a landing craft with an advance guard of purchasing agents and
OleMash [197]

Answer:

Explanation:

Let the velocity of lander with respect to earth be v .

In relativistic mechanism the expression for relative velocity is

v_r = \frac{v -u}{1-\frac{uv}{c^2}}

Given u = .6c , v_r = .8 c

Substituting the values

.8c = \frac{v -0.6c}{1-\frac{.6c\times v}{c^2} }

.8c-.48v = v - .6c

v = .946c

b )

Distance in terms of time = .2 ly

In relativistic mechanism , expression for relativistic time is given by the following relation

t = \frac{t_0}{\sqrt{1-\frac{v^2}{c^2} }}

Substituting v = .946c

t₀ = .2

t = \frac{.2}{\sqrt{1-\frac{0.946\times .946c^2}{c^2}}}

.2 / √.1050

= .62 ly

distance to the Earth at the time of lander launch, as observed by the aliens will be .62 ly.

8 0
4 years ago
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