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andre [41]
2 years ago
5

When two identical resistors are connected in series across ideal battery, total power dissipated by them is P. Now both are con

nected in parallel and same battery is connected across the combination. Now find the total power dissipated by both of them.
Physics
1 answer:
Art [367]2 years ago
4 0

Answer:

4 P

Explanation:

V = IR

     when they are in series   R = 2 r

     when they are in parallel R = 1/2 r

         so current will increase by a factor of 4  when they are in parallel

              and power used will also increase by a factor of 4  to  4 P

Power = IV       when I now becomes 4 I     power becomes 4 P

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A 10.0 L balloon contains helium gas at a pressure of 660 mmHg . What is the final pressure, in millimeters of mercury, of the h
Ksivusya [100]

Answer:

(a)= 264mmHg

(b)= 2000mmHg

(c)474.82mmHg

(d)= 511.63mmHg

Explanation:

the question deals with boyles law, which states that the volume of a given mass of gas at constant temperature is inversely proportional to its pressure

V ∝ 1/P

P₁V₁ = P₂V₂

making V₂ as the subject of formular

P₂ = P₁V₁/ V₂

with a volume of  25.0L

P₂ = 660×10 / 25

= 264mmHg

with a volume of 3.30 L

P₂  = 660 × 10 / 3.30

= 2000mmHg

with a volume of 13900 mL

= 13.9L

P₂  =660× 10 / 13.9

474.82mmHg

with a volume of 12900 mL

P₂ =660×10 / 12.9

= 511.63mmHg

6 0
3 years ago
lood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobi
uysha [10]

Answer:

P_1 - P_2 =219.62\ Pa

Explanation:

given,

density of blood = 1060 kg/m³

v₂ = 0.800 m/s

v₁ = 0.475 m/s

change in pressure calculation

using Bernoulli's equation

P_1 +\dfrac{1}{2}\rho v_1^2 = P_2 + \dfrac{1}{2}\rho v_2^2

both are at same level

P_1 - P_2 =\dfrac{1}{2}\rho (v_2^2- v_1^2)

P_1 - P_2 =\dfrac{1}{2}1060\times (0.8^2- 0.475^2)

P_1 - P_2 =219.62\ Pa

the change in pressure is equal to 219.62 Pa

5 0
3 years ago
A 25 kg lamp is hanging from a rope. What is the tension force being supplied by the rope?
Elan Coil [88]

The tension force being supplied by the rope is 245 N.

<h3>What is tension force?</h3>
  • Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.

The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;

T = mg

where;

  • m is the mass = 25 kg
  • g is acceleration due to gravity = 9.8 m/s²

T = 25 x 9.8

T = 245 N

Thus, the tension force being supplied by the rope is 245 N.

Learn more about tension force here: brainly.com/question/12797227

7 0
2 years ago
Which of the following would have the smallest gravitational attraction between the two masses?
expeople1 [14]

Answer: Distance= 100,000 km

   Mass= 15 million kg        Mass= 5 million kg

3 0
3 years ago
Read 2 more answers
A ‘thermal tap’ used in a certain apparatus consists of a silica rod which
abruzzese [7]

Correct question is;

A thermal tap used in a certain apparatus consists of a silica rod which fits tightly inside an aluminium tube whose internal diameter is 8mm at 0°C.When the temperature is raised ,the fits is no longer exact. Calculate what change in temperature is necessary to produce a channel whose cross-sectional is equal to that of the tube of 1mm. (linear expansivity of silica = 8 × 10^(-6) /K and linear expansivity of aluminium = 26 × 10^(-6) /K).

Answer:

ΔT = 268.67K

Explanation:

We are given;

d1 = 8mm

d2 = 1mm

At standard temperature and pressure conditions, the temperature is 273K.

Thus; Initial temperature; T1 = 273K,

Using the combined gas law, we have;

P1×V1/T1 = P2×V2/T2

The pressure is constant and so P1 = P2. They will cancel out in the combined gas law to give:

V1/T1 = V2/T2

Now, volume of the tube is given by the formula;V = Area × height = Ah

Thus;

V1 = (πd1²/4)h

V2 = (π(d2)²/4)h

Thus;

(πd1²/4)h/T1 = (π(d2)²/4)h/T2

π, h and 4 will cancel out to give;

d1²/T1 = (d2)²/T2

T2 = ((d2)² × T1)/d1²

T2 = (1² × T1)/8²

T2 = 273/64

T2 = 4.23K

Therefore, Change in temperature is; ΔT = T2 - T1

ΔT = 273 - 4.23

ΔT = 268.67K

Thus, the temperature decreased to 268.67K

6 0
3 years ago
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