Answer:
Solution B: [OH-] = 1×10^–6 M
Solution C: [OH-] = 1×10^–6 M
Explanation:
Solution B:
Hydronium ion concentration, [H3O+] = 9.99×10^–9 M
Hydroxide ion concentration, [OH-] = ?
The Hydroxide ion concentration, [OH-] can be obtained as follow:
[H3O+] × [OH-] = 1×10^–14
9.99×10^–9 × [OH-] = 1×10^–14
Divide both side by 9.99×10^–9
[OH-] = 1×10^–14 / 9.99×10^–9
[OH-] = 1×10^–6 M
Therefore, the Hydroxide ion concentration, [OH-] is 1×10^–6 M
Solution C:
Hydronium ion concentration, [H3O+] = 0.000777 M
Hydroxide ion concentration, [OH-] = ?
The Hydroxide ion concentration, [OH-] can be obtained as follow:
[H3O+] × [OH-] = 1×10^–14
0.000777 × [OH-] = 1×10^–14
Divide both side by 0.000777
[OH-] = 1×10^–14 / 0.000777
[OH-] = 1.29×10^–11 M
Therefore, the Hydroxide ion concentration, [OH-] is 1.29×10^–11 M
