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Reika [66]
3 years ago
15

What is a contributor of global warming?

Chemistry
2 answers:
iogann1982 [59]3 years ago
8 0
Carbon dioxide emissions from, well, whatever emits CO2 really. 
svet-max [94.6K]3 years ago
7 0

Answer:    B. Carbon dioxide

Explanation:  Global warming arises due to the emission of gases which are accumulated in the atmosphere, that is, the layer of these gases increases in an atmosphere, and prevents the reflected sun rays from the ground to leave the atmosphere. Such a higher amount of sunshine-heat which is higher than necessary, remains in the atmosphere and heats the surface of the earth, which is the effect of the greenhouse. These are gases produced by combustion of fossil fuels, and during this combustion they are emitted into the atmosphere. Gases that cause the greenhouse effect are carbon dioxide, methane and nitrous oxide. The problem is that fossil fuels are used to produce electricity, in agriculture and transport. Global warming has drastically increased over the past decades, and if preventive measures which involving the use of alternative fuels are not undertaken, the catastrophic consequences, which are already visible, will be even greater.

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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
The ka values for several weak acids are given below. which acid (and its conjugate base) would be the best buffer at ph = 8.0?
Pie
One of the best buffer choice for pH = 8.0 is Tris with Ka value of  6.3 x 10^-9.

To support this answer, we first calculate for the pKa value as the negative logarithm of the Ka value: 
     pKa = -log Ka

For Tris, which is an abbreviation for 2-Amino-2-hydroxymethyl-propane-1,3 -diol and has a Ka value of 6.3 x 10^-9, the pKa is
     pKa = -log Ka
            = -log (6.3x10^-9)
            = 8.2

We know that buffers work best when pH is equal to pKa:
     pKa = 8.2 = pH 

Therefore Tris would be a best buffer at pH = 8.0.
7 0
3 years ago
Read 2 more answers
What is the mass number of an atom with 17 protons, 17 electrons, and 20 neutrons?
astra-53 [7]
The mass number of this particular element is 37

An element with 17 protons will ALWAYS be chlorine.
The mass number is found by adding the element’s protons and neutrons.
protons+neutrons=mass number

Here is the math if needed,
17+20=37

Therefore the mass number is 37

I hope this helped!
3 0
3 years ago
What is the correct chemical equation for the reaction between methane and oxygen to produce carbon dioxide and water?
kodGreya [7K]

Answer:

The answer to your question is:   CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

Explanation:

Methane = CH₄

Oxygen = O

Carbon dioxide = CO₂

Water = H₂O

                      CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

        This is the balanced equation

                 

3 0
3 years ago
Could someone help me with this?
Varvara68 [4.7K]

Solving part-1 only

#1

KMnO_4

  • Transition metal is Manganese (Mn)

#2

Actually it's the oxidation number of Mn

Let's find how?

\\ \tt\Rrightarrow x+1+4(-2)=0

\\ \tt\Rrightarrow x+1-8=0

\\ \tt\Rrightarrow x-7=0

\\ \tt\Rrightarrow x=+7

  • x is the oxidation number

#3

  • Purple as per the color of potassium permanganate

#4

\boxed{\begin{array}{c|c|c}\boxed{\bf Tube} &\boxed{\bf Charge} &\boxed{\bf No\:of\; electrons\: loss}\\ \sf 2 &\sf +6 &\sf 6e^-\\ \sf 3& \sf +2 &\sf 2e- \\ \sf 4 &\sf 4 &\sf 4e^-\end{array}}

7 0
2 years ago
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