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yanalaym [24]
3 years ago
7

Because sucrose is hygroscopic, how should it be properly stored in a cupboard

Chemistry
1 answer:
kirza4 [7]3 years ago
4 0

Sucrose is stored in dry and closed container, sealed properly.

Explanation:

  • Sucrose is nothing but the table sugar which we use daily in our life.
  • Sucrose is formed by the combination of fructose and glucose so, it called a disaccharide because two monosaccharides are converted to form sucrose.
  • It is a hygroscopic substance. The hygroscopic substance is which is easily vulnerable to water absorption. They tend to absorb water if they are being exposed to humid places.
  • Hence, it should be kept in a dry and close container, sealed properly.
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A solution is 40 cetic acid by mass. the density of this solution is 1.049 g/ml. Calculate the mass of pure acetic acid in 220 m
taurus [48]

The mass of pure acetic acid in 220 ml of the given solution at 20°C is 92.311 g

<h3>What is Acetic acid?</h3>

Acetic acid is a type of carboxylic acid and also known as ethanoic acid

Its formula is CH₃COOH.

It is an organic compound and is a colorless liquid

It is mostly used in the production of vinegar

40 % acetic acid by mass means,

40 g of acetic acid is dissolved in 100 g of solution.

The density of solution at 20°C,

\rho = 1.049 g/ml

We know,

\rho = \frac{m}{V}

V = \frac{m}{\rho}

The volume of the solution, V = \frac{100}{1.049} = 95.33 ml

95.33 ml of solution contains 40 g of pure Acetic acid

220 ml of solution contains\frac{40 \times 220}{95.33} = 92.311 g of pure Acetic acid

Thus, the mass of pure Acetic acid in 220 ml of solution at 20°C is 92.311 g

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7 0
1 year ago
A system fitted with a piston expands when it absorbs 53.1 ) of heat from the surroundings. The piston is working against a pres
Hoochie [10]

Answer:

d. 60.8 L

Explanation:

Step 1: Given data

  • Heat absorbed (Q): 53.1 J
  • External pressure (P): 0.677 atm
  • Final volume (V2): 63.2 L
  • Change in the internal energy (ΔU): -108.3 J

Step 2: Calculate the work (W) done by the system

We will use the following expression.

ΔU = Q + W

W = ΔU - Q

W = -108.3 J - 53.1 J = -161.4 J

Step 3: Convert W to atm.L

We will use the conversion factor 1 atm.L = 101.325 J.

-161.4 J ×  1 atm.L/101.325 J = -1.593 atm.L

Step 4: Calculate the initial volume

First, we will use the following expression.

W = - P × ΔV

ΔV = - W / P

ΔV = - 1.593 atm.L / 0.677 atm = 2.35 L

The initial volume is:

V2 = V1 + ΔV

V1 = V2 - ΔV

V1 = 63.2 L - 2.35 L = 60.8 L

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2 years ago
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The metric system prefix for the above quantity would be D. Micro. Which is 10^-6.
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