Each 100 cm3 of air, constitutes 78cm3 nitrogen, 21cm3 oxygen and 1cm3 constitutes of other gases like Argon, ozone, carbon dioxide and water vapour in small amounts.
the answer i believe is b:saltation, which is a form of wind erosion
Answer:
Explanation:
Given data:
Mass of N₂ = 48.7 g
Moles of N₂ = ?
Molecules of N₂ = ?
Mass of N₂O = ?
Moles of N₂O = ?
Atoms of N₂O = ?
Solution:
Chemical equation:
2N₂ + O₂ → 2N₂O
Number of moles of N₂:
Number of moles = mass/ molar mass
Number of moles = 48.7 g / 28 g/mol
Number of moles = 1.74 mol
Number of molecules of N₂:
1 mole = 6.022 × 10²³ molecules
1.74 mol× 6.022 × 10²³ molecules/1 mol
10.5 × 10²³ molecules
Now we will compare the moles of N₂ with N₂O from balance chemical equation:
N₂ : N₂O
2 : 2
1.74 : 1.74
Moles of N₂O:
1.74 mol
Mass of N₂O:
Mass = number of moles × molar mass
Mass = 1.74 mol × 44 g/mol
Mass = 76.56 g
Answer:
4.50 g of H₂O
Explanation:
The Balance chemical equation is
2 H₂ + O₂ = 2 H₂O
Step 1: Calculate Limiting Reagent
Moles of H₂
Mole = 2 g / 2.02 g/mol = 0.99212 mol
Moles of O₂
Mole = 4 g / 32.00 g/mol = 0.125 mol
Mole ratio of H₂ : O₂ is 2 : 1. Hence, 0.99212 mol of H₂ will need 0.49606 mol of O₂. This means O₂ is limiting reagent.
Step 2: Calculate Moles of H₂O
0.125 mol of O₂ will produce 0.250 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.
Step 3: Calculate mass of H₂O
Mass = 0.250 mol × 18.02 g/mol = 4.50 g of H₂O
