Answer:
4777.09grams
Explanation:
To find the mass of oxygen, we first need to find the mass of potassium sulfate (K2SO4).
Since there are 4.50 x 10^25 formula units of potassium sulfate, we can find the number of moles in K2SO4 by dividing by Avagadros number (6.02 × 10^23 units). That is;
number of moles of K2SO4 (n) = 4.50 x 10^25 ÷ 6.02 × 10^23
= 0.747 × 10^ (25-23)
= 0.747 × 10^2
= 7.47 × 10^1 moles
Mass in grams of K2SO4 can be calculated thus: molar mass of K2SO4 × moles
= 174.252 g/mol × 7.47 × 10^1 moles
= 13016.62grams.
Since mass of oxygen in 1 mol of K2SO4 = O4 = 63.996 g/mol
We find the percentage by mass of oxygen in K2SO4 as follows:
= 63.996/174.252 × 100
= 0.367 × 100
= 36.7% by mass of oxygen.
This means that in 1gram of K2SO4, there are 0.367gram of Oxygen. Hence, in 13016.62grams (4.50 x 10^25 units) of K2SO4, there will be;
0.367 × 13016.62
= 4777.09grams of oxygen.
Answer:
713mmHg
Explanation:
By using Dalton's law of partial pressure, the pressure outside the gas container is equal to the pressure inside it and this pressure equals the sum of the pressures of water and the gas.
i.e, P(total) = P(gas) + P(water)
P(gas) = P(total) - P(water)
P(gas) = 735 - 22
P(gas) = 713mmHg
Answer:
Their identity changes in both Reaction A and Reaction B.
The best answer is Titanium