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3 years ago

Does this make sense?

Chemistry

2 answers:

elena-s [515]3 years ago

5 0

Makes sense to me but I would try and add another sentence in the middle to smooth it out some

iVinArrow [24]3 years ago

4 0

Answer:

Yes, but you have a bit of grammar mistakes.

Explanation:

Mount. Vesuvius were an African boundary....

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calculate how many Liters of 0.50 M silver nitrate solution you will need to provide the 2.4x10^-3 moles of silver nitrate

wlad13 [49]

Answer:

4.8x10⁻³ Liters are required

Explanation:

Molarity is an unit of concentration in chemistry defined as the ratio between moles of solute (In this case, silver nitrate) and liters of solution.

The 0.50M solution contains 0.50 moles of silver nitrate per liter of solution.

To provide 2.4x10⁻³ moles Silver nitrate are required:

2.4x10⁻³ moles * (1L / 0.50 moles) =

<h3>4.8x10⁻³ Liters are required</h3>

8 0

2 years ago

Give the name of this alcohol.

solong [7]

Answer:

An alcohol is an organic compound with a hydroxyl (OH) functional group on an aliphatic carbon atom. Because OH is the functional group of all alcohols, we often represent alcohols by the general formula ROH, where R is an alkyl group. Alcohols are common in nature.

Explanation:

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2 years ago

IS IT BETTER OR WORSE TO WORKOUT/EXERCISE IN DARK OR LIGHT COLORED CLOTHING?

soldi70 [24.7K]

Answer:

Dark clothing

Explanation:

Dark clothing like black absorbs/locks in heat. Since exercise is to burn and tonify our body from unwanted fat it is important to sweat. This is where heat comes in and helps you sweat

3 0

2 years ago

Read 2 more answers

A 3.4 g sample of an unknown monoprotic organic acid composed of C,H, and O is burned in air to produce 8.58 grams of carbon dio

Pavlova-9 [17]

Answer:

$C_7H_6O_2$

Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

(1) In this case, since 8.58 g of carbon dioxide are released, we can first compute the moles of carbon in the compound:

$n_C=8.58gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.195molC$

And the moles of hydrogen due to the produced 1.50 grams of water:

$n_H=1.50gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O} =0.166molH$

Next, to compute the mass and moles of oxygen, we need to use the initial 3.4 g of the acid:

$m_O=3.4g-0.195molC*\frac{12.01gC}{1molC}-0.166molH*\frac{1.01gH}{1molH} =0.89gO\\\\n_O=0.89gO*\frac{1molO}{16.0gO}=0.0556molO$

Thus, the subscripts in the empirical formula are:

$C=\frac{0.195}{0.0556}=3.5 \\\\H=\frac{0.166}{0.0556}=3\\\\O=\frac{0.0556}{0.0556}=1\\\\C_7H_6O_2$

As they cannot be fractions.

(2) In this case, since the acid is monoprotic, we can compute the moles by multiplying the concentration and volume of KOH:

$n_{KOH}=0.279L*0.1mol/L\\\\n_{KOH}=0.0279mol$

Which are equal to the moles of the acid:

$n_{acid}=0.0279mol$

And the molar mass:

$MM_{acid}=\frac{3.4g}{0.0279mol} =121.86g/mol$

(3) Finally, since the molar mass of the empirical formula is:

7*12.01 + 6*1.01 + 2*16.00 = 122.13 g/mol

Thus, since the ratio of molar masses is 122.86/122.13 = 1, we infer that the empirical formula equals the molecular one:

$C_7H_6O_2$

Best regards!

8 0

3 years ago

What is the specific heat of iron, if it requires 1120 J of heat energy to raise the

IRISSAK [1]

Answer:

Specific heat is defined as the amount of heat needed to raise the temperature by one degree celsius. Therefore, in 1 kg there are 100 grams so, 10 grams equal 0.01 Kg. Thus, calculate the specific heat value as follows. Thus, we can conclude that specific heat of the given metal is 0.5 .

Explanation:

4 0

2 years ago