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4 years ago

What are three areas are the natural sciences commonly divided

1 answer:

5 0

Today, natural sciences are more commonly divided into life sciences, such as botany and zoology; and physical sciences, which include physics, chemistry, geology, astronomy and materials science.

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Libre points paa sa lahat follow nyo po ako salamat po

nikitadnepr [17]

Answer:

Explanation:

<h2>PLEASE MARK ME BRAINLIEST AND FOLLOW ME LOTS OF LOVE FROM MY HEART'AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

6 0

3 years ago

Assume that helium behaves as an ideal monatomic gas. If 2 moles of helium undergo a temperature increase of 100 k at constant p

Helga [31]

4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

<h3>What are Noble Gases ?</h3>

The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.

They are called noble gases because they are so majestic that they do not react with anything in general.

The work done can be calculated by the formula

Q=n Cp ΔT

Cp= ( 1+ f/2)R

R= 8.3144598 J. mol-1.

Cp = (1+3/2) * 8.314

Cp = 5*8.314/2

Q= 2 * 5 *8.314 *100/2

Q = 4157 J

Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.

To know more about Noble Gas

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3 0

2 years ago

The critical pressure of carbon dioxide is 72.7 atm. What is this value in units of pascals?

Blizzard [7]

Answer: 7366.328 kPa
explanation: the critical pressure of carbon dioxide is 72.7 atm.

8 0

4 years ago

what is the empirical formula for a substance if a 1.000 g sample of it contains 0.262 grams of nitrogen, 0.075 grams of hydroge

Sonbull [250]

Here are the steps for finding an emprical formula.

To begin, we need to change the grams to a percentage. We can simply take the number and call it our percentage. (i.e 0.262%)

Then, we have a simply stoichiometry step. We put our starting number over 1, as usual. The next "Step" is putting in the molar mass of that particular element on the bottom, with one on top. It should look like this:

0.262% N 1
-------------- x ----------------
1 14.007g N

We would then divide those two numbers to get our answer. Repeat for the other elements included, until we have all of them done.

After that, we need to find the smallest number that was the answer to one of the equations. For example, if the product of Hydrogen was the smallest formed, we would locate that number. We then divide ALL of our answers by that smallest number.

Remember, whenever doing empirical formulas, significant figures matter.

Once we have our smallest numbers, we need to round our numbers to the nearest whole number. HOWEVER, to do this we need to multiply all of the numbers by the SAME whole number.

For example, if one of our numbers was 1.33, we would multiply by 3 to get a whole number. However, we would also need to multiply the rest of our products by the same number. If we do not get close to whole numbers (you can round), we need to try with multiplying a different number.

Then, we need to take those whole numbers we got for each number, and plug in to make a compound. For example, if our products were 6 for nitrogen, 3 for hydrogen, and 2 for chlorine, our final empirical formula would be N6H3Cl2.

Hope I could help! If it was a bit wordy please let me know and I'd be more than willing to clarify.

4 0

3 years ago

When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many

Mumz [18]

Answer:

1.61 g Na₂S

Explanation:

To find the mass of sodium sulfide (Na₂S) generated from hydrogen sulfide (H₂S) and sodium hydroxide (NaOH), you need to (1) construct the balanced chemical equation, then (2) calculate the molar masses of each molecule involved, then (3) convert grams of each reagent to grams of the product (via the molar masses and mole-to-mole ratio from equation coefficients), and then (4) determine the limiting reagent and final answer. It is important to arrange the conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

(Step 1)

The unbalanced equation:

H₂S + NaOH ---> Na₂S + H₂O

Reactants: 3 hydrogen, 1 sulfur, 1 sodium, 1 oxygen

Products: 2 hydrogen, 1 sulfur, 2 sodium, 1 oxygen

The balanced equation:

H₂S + 2 NaOH ---> Na₂S + 2 H₂O

Reactants: 4 hydrogen, 1 sulfur, 2 sodium 2 oxygen

Products: 4 hydrogen, 1 sulfur, 2 sodium, 4 oxygen

(Step 2)

Molar Mass (H₂S): 2(1.008 g/mol) + 32.065 g/mol

Molar Mass (H₂S): 34.081 g/mol

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.998 g/mol

Molar Mass (Na₂S): 2(22.990 g/mol) + 32.065 g/mol

Molar Mass (Na₂S): 78.045 g/mol

(Step 3)

1.50 g H₂S 1 mole 1 mole Na₂S 78.045 g
----------------- x ---------------- x -------------------- x ----------------- =
34.081 g 1 mole H₂S 1 mole

= 3.43 g Na₂S

1.65 g NaOH 1 mole 1 mole Na₂S 78.045 g
-------------------- x ---------------- x ----------------------- x ---------------- =
39.998 g 2 moles NaOH 1 mole

= 1.61 g Na₂S

(Step 4)

Because NaOH generates less product, it will run out before all of the H₂S is used. This makes NaOH the limiting reagent and the final answer 1.61 grams Na₂S.

5 0

2 years ago