Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:
The equilibrium expression is:
![Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:
The equilibrium expression is:
![Keq=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.
Positron emission = emission of a positron and a neutrino when a proton is convert into a neutron. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron
It's a spontaneous reaction for some nucleus.
eg:
Positron = e+
Neutrino=ve
O-15 --> N-15 + e+ +ve
Electron capture= A nucleus absorb an electron while a proton is convert in a neutron and emit a neutrino. The total number of particles in the nucleus doesn't change, -1 proton +1 neutron
eg:
Al-26 +e- --> Mg-26 + ve
Electron capture and positron emission are two mechanisms to explain the decay of some unstable isotopes. Electron capture is usually observed when the energy difference between the initial and final state is low. Mainly because of the larger amount of kinetic energy need for the expulsion of two particles with the positron emission mechanism.
Answer:
D
Explanation:
The proberties of the substances that are produced are different from the properties of the original substances.
At a definite amount of solute and at a definite tempreture it is dissolved in utane above that it remain unsoluble
By adding catalyst e.g. mno2,vanadium oxide
by increasing the temperature if it is an exothermic reaction
by also decreasing if it is an endothermic reaction
