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4 years ago

11

What's missing from the graph

2 answers:

sukhopar [10]4 years ago

5 0

The title is missing

tatuchka [14]4 years ago

3 0

Answer: title

Explanation:

just did the question

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50.g of NaNO3 was dissolved in 1250 mL of water. what is the molality of the solution? [ Molar mass of NaNO3 = 85 g/mol

Viefleur [7K]

Answer:

Approximately $0.47\; \rm mol \cdot L^{-1}$ (note that $1\; \rm M = 1 \; \rm mol \cdot L^{-1}$ .)

Explanation:

The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this $\rm NaNO_3$ solution in water,

Let $n$ be the number of moles of the solute in the whole solution. Let $V$ represent the volume of that solution. The formula for the molarity $c$ of that solution is:

$\displaystyle c = \frac{n}{V}$ .

In this question, the volume of the solution is known to be $1250\; \rm mL$ . That's $1.250\; \rm L$ in standard units. What needs to be found is $n$ , the number of moles of $\rm NaNO_3$ in that solution.

The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of $\rm NaNO_3$ is $85\; \rm g \cdot mol^{-1}$ means that the mass of one mole of

$\displaystyle n = \frac{m}{M}$ .

For this question,

$\begin{aligned}&n\left(\mathrm{NaNO_3}\right) \\ &= \frac{m\left(\mathrm{NaNO_3}\right)}{M\left(\mathrm{NaNO_3}\right)}\\&= \frac{50\; \rm g}{85\; \rm g \cdot mol^{-1}} \\& \approx 0.588235\; \rm mol\end{aligned}$ .

Calculate the molarity of this solution:

$\begin{aligned}c &= \frac{n}{V} \\&= \frac{0.588235\; \rm mol}{1.250\; \rm L} \\&\approx 0.47\;\rm mol \cdot L^{-1}\end{aligned}$ .

Note that $1\; \rm mol \cdot L^{-1}$ (one mole per liter solution) is the same as $1\; \rm M$ .

8 0

3 years ago

If you had 1.00 kg of each kind of hardware, how many boxes of each would you<br> have?

dusya [7]

The number of boxes is calculated by dividing the

total mass of hardware boxes by 1.00 kg

<h3>What is a hardware?</h3>

A hardware is a physical component of a system that can be touched and felt.

Because hardware are physical components, they always have a given mass.

Assuming, several hardware each of mass 1.00 kg is available to be chosen from.

Also, assuming that the sum total of the mass of all the hardware is known.

The number of boxes can be calculated as follows:

total mass of hardware/1.00 kg

Therefore, the number of boxes is obtained by dividing the sum of the mass of the boxes by 1.00 kg.

Learn more about hardware and mass at: brainly.com/question/25698914

7 0

3 years ago

What are the noble gases on the periodic table?

Lynna [10]

Helium,neon,argon,krypton, and xenon

8 0

3 years ago

A reaction will be spontaneous only at low temperatures if both ΔH and ΔS are negative. For a reaction in which ΔH = −310.1 kJ/m

ruslelena [56]

Answer:

3211.12 K

Explanation:

The expression for the standard change in free energy is:

$\Delta G=\Delta H-T\times \Delta S$

Where,

$\Delta G$ is the change in the Gibbs free energy.

T is the absolute temperature. (T in kelvins)

$\Delta H$ is the enthalpy change of the reaction.

$\Delta S$ is the change in entropy.

For reaction to be spontaneous, $\Delta G$

Given, $\Delta H=-310.1\ kJ/mol=-310100\ J/mol$

$\Delta S=-89.00\ J/K.mol$

So,

$\Delta H-T\times \Delta S$

Thus, applying values as:-

$-310100-T\times (-89.00)$

So, T = 3484.27 K

The conversion of T( °C) to T(K) is shown below:

T( °C) = T(K) - 273.15

So,

T = (3484.27 - 273.15) K = 3211.12 K

<u>The temperature below which the reaction is spontaneous is:- 3211.12 K </u>

6 0

4 years ago

Nonliving things have cells.<br><br> True<br> False

Whitepunk [10]

The answer is false.

3 0

4 years ago

Read 2 more answers