If two quantitative variables are highly correlated, does that necessarily result in causation?

Susie lost $15 on Monday. Her mom was upset, but gave her another $20. She lost another $13 today. Write an integer to represent

maria [59]

Answer:

Step-by-step explanation:

If you add 13 +15 you get 28$ if we were to write that as an integer out of 20 it would be 28/20 but as an improper fraction, it would need to be simplified into 1 and 8/20 ( 1 8/20)

If you are looking how much she lost out of the 20 she lost today it would be 13/20

Hope this helps

Dont lose ur money

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4 0

2 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago

In the diagram, the length of segment QV is 15 units.

Andrews [41]

Answer:

The answer is 15 units.

Step-by-step explanation:

The reason it is 15 units is because We know that QV = 15 and TQ = TS, QV = SV;4 x - 1 = 154 x = 15 + 14 x = 16x = 16 : 4 = 4 henceforth the answer being 15 units

6 0

3 years ago

Read 2 more answers

Complete the coordinate proof of the theorem.

mojhsa [17]

C(a,b), because the x-coordinate( first coordinate) is a (seeing as it is situated directly above point B, which also has an x-coordinate of a) and the y-coordinate ( second coordinate) is b (seeing as it is situated on the same horizontal level as point D, which also has a y-coordinate of b)

the length of AC can be calculated with the theorem of Pythagoras:

length AB = a - 0 = a
length BC = b - 0 = b

seeing as the length of AC is the longest, it can be calculated by the following formula:

It is called "Pythagoras' Theorem" and can be written in one short equation:

a^2 + b^2 = c^2 (^ means to the power of by the way)

in this case, A and B are lengths AB and BC, so lenght AC can be calculated as the following:

a^2 + b^2 = (length AC)^2
length AC = √(a^2 + b^2)

Extra information: Seeing as the shape of the drawn lines is a rectangle, lines AC and BD have to be the same length, so BD is also √(a^2 + b^2). But that is also stated in the assignment!

3 0

3 years ago

Read 2 more answers

A daycare charges $115 per week for one child. Each additional child costs $65 for the week. If a family pays $505 for a week, h

valentinak56 [21]

Answer:

7 children

Step-by-step explanation:

$505-$115= $390

$390÷$65= 6

6+1= 7

4 0

3 years ago