(20/23) times 100 is 87%
now the answer asks for percentage ERROR
100-87 =13
so answer is C
Answer:
308 g
Explanation:
Data given:
mass of Fluorine (F₂) = 225 g
amount of N₂F₄ = ?
Solution:
First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄
Reaction:
2F₂ + N₂ -----------> N₂F₄
Now look at the reaction for mole ratio
2F₂ + N₂ -----------> N₂F₄
2 mole 1 mole
So it is 2:1 mole ratio of Fluorine to N₂F₄
As we Know
molar mass of F₂ = 2(19) = 38 g/mol
molar mass of N₂F₄ = 2(14) + 4(19) =
molar mass of N₂F₄ = 28 + 76 =104 g/mol
Now convert moles to gram
2F₂ + N₂ -----------> N₂F₄
2 mole (38 g/mol) 1 mole (104 g/mol)
76 g 104 g
So,
we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.
Apply unity formula
76 g of F₂ ≅ 104 g of N₂F₄
225 g of F₂ ≅ X of N₂F₄
Do cross multiplication
X of N₂F₄ = 104 g x 225 g / 76 g
X of N₂F₄ = 308 g
So,
308 g N₂F₄ can be produced from 225 g F₂
Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.
<h3>What is a weak base ionization constant?</h3>
The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.
The reaction for HCO₃ is given as:
HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O
The value of Ka for the given reaction will be:
Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]
Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.
Learn more about the weak ionization constant here:
brainly.com/question/27200344
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The major reaction would be addition
Answer: 2.408×10^24 atoms
Explanation:
Applying the formula
No. moles= (no. Of atoms)/Avogadro's number
4 = n/6.02×10^23
no. of atoms= 2.408×10^24 atoms
