The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?
Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of 
to 
.
Explanation:
Given: Mass = 500 g
Initial temperature =
Final temperature =
The standard value of specific heat of ethyl alcohol is 
.
Formula used to calculate the heat energy is as follows.
where,
q = heat energy
m = mass of substance
C = specific heat
= initial temperature
= final temperature
Substitute the values into above formula as follows.
![q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J](https://tex.z-dn.net/?f=q%20%3D%20m%20%5Ctimes%20C%20%5Ctimes%20%28T_%7B2%7D%20-%20T_%7B1%7D%29%5C%5C%3D%20500%20g%20%5Ctimes%202.46%20J%2Fg%5E%7Bo%7DC%20%5Ctimes%20%5B150%20-%20%28-40%29%5D%5E%7Bo%7DC%5C%5C%3D%20233700%20J)
Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of to .
10.0 J
if it was 10.01 it would be significant, but its 10.0 which makes it a whole number
Answer:
1. Hot air is less dense and has moved upward allowing cool air to move downward which is less dens
(Convection current)
2. The ceiling has transferred heat to him by radiation.
Explanation:
During the day when air is heated as a result of the ceiling transferring heat to it, it becomes less dens and it gains energy, which make it lighter in weight than cooler air, this hot air moves upward allowing cooler air to move downward.
The gravitational force between the spheres is
where <em>G</em> = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
where <em>g</em> = 9.80 m/s².
The ratio between the two forces is then
