Answer
given,
ω₁ = 0 rev/s
ω₂ = 6 rev/s
t = 11 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
11 α = 6 - 0
= 0.545 rev/s²
The angular displacement
θ₁= ωi t + (1/2) α t²
θ₁= 0 + (1/2) (0.545)(11)^2
θ₁= 33 rev
case 2
ω₁ = 6 rev/s
ω₂ = 0 rev/s
t = 14 s
Using equation of rotational motion
The angular acceleration is
ωf - ωi = α t
14 α = 0 - 6
= - 0.428 rev/s²
The angular displacement
θ₂= ωi t + (1/2) α t²
θ₂= 6 x 14 + (1/2) (-0.428)(14)^2
θ₂= 42 rev
total revolution in 25 s is equal to
θ = θ₁ + θ₂
θ = 33 + 42
θ = 75 rev
You want to draw a free body diagram of the forces on the sled in the horizontal x-direction.
If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.
The angle made with the x-axis is cosine of the angle theta.
Please see picture attached.
The time when the two players will collide is 0.96 s.
The equation of motion of the two players is given as;
x1 = 0.1 m + (–3.9 m/s )t
x2 = –6.3 m + (2.8 m/s )t
The time when the two players collide, their displacement is equal or the difference in their position will be zero.

Thus, the time when the two players will collide is 0.96 s.
Learn more here: brainly.com/question/18033352
Answer:
a. the amount of work done on a system is dependent of pathway
Explanation:
The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system.
ΔU = Q - W
Where;
Q, the net heat transfer into the system depends on the pathway
W, the net work done by the system also depends on the pathway
But, ΔU, the change in internal energy is independent of pathway
Therefore, the correct option is "A"
a. the amount of work done on a system is dependent of pathway
Force is equal to mass x acceleration. The heavyweight is packing both greater acceleration and mass than the tissue paper.
When his fist comes in contact with the paper, the tissue reacts by exerting its own opposite force, providing a tiny bit of resistance until the fist breaks it apart and passes through.
The fist, although by a a very tiny amount, is decelerated (slowed down) by the paper before it breaks through.