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AfilCa [17]
3 years ago
13

A gas sample is confined within a chamber that has a movable piston. A small load is placed on the piston; and the system is all

owed to reach equilibrium. If the total weight of the piston and load is 70.0 N and the piston has an area of 5.0 × 10 –4 m 2 , what is the pressure exerted on the piston by the gas? Note: Atmospheric pressure is 1.013 × 10 5 Pa.
Physics
1 answer:
timurjin [86]3 years ago
7 0

Explanation:

It is given that,

Total weight of the piston, W = F = 70 N

Area of the piston, a=5\times 10^{-4}\ m^2

Let P is the pressure exerted on the piston by the gas. The force per unit area is called the pressure exerted pressure of the gas. Mathematically, it is given by :

P=\dfrac{F}{A}

P=\dfrac{70\ N}{5\times 10^{-4}\ m^2}

P=1.4\times 10^5\ Pa

We know that the atmospheric pressure is given by :

P_o=1.013\times 10^5\ Pa

So, the pressure is given by :

p=P+P_o

p=1.4\times 10^5+1.013\times 10^5

p=2.41\times 10^5\ Pa

Hence, this is the required solution.

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Amiraneli [1.4K]

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The value of the measured voltage on each resistor can be seen as to be exactly as calculated, which is 1/3 of the voltage input. The total current can be calculated as:

I=\frac{V}{R+R+R}=\frac{15}{3*3}=\frac{15}{9}\approx1.7A

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(c) How did the equivalent resistance, voltage drop across each resistor, total current, and total voltage change as you added resistors in series to the circuit?

The voltage drop on each resistor will decrease once you add more resistors, as there will be more total resistance, and thus less current. As the resistance of each resistor is constant, the relation V=RI given by Ohm's law will be reduced.

5 0
1 year ago
A metal wire has a resistance of 14.00 Ω at a temperature of 25.0°C. If the same wire has a resistance of 14.55 Ω at 90.0°C, wha
aliina [53]

Answer:

13.52 Ω

Explanation:

coefficient of thermal resistance be α

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R₂₅ = R₀ + α x 25

R₉₀ = R₀ + α x 90

R₉₀ - R₂₅ = 65 x α

α = (R₉₀ - R₂₅ )/ 65

= (14.55 - 14) / 65

=   .55 / 65 Ω per °C,

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14 = R₀ + (.55 / 65 )x 25

=  R₀ + .2115

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= 13.7885 -(  .55 / 65) x 32

=  13.7885 - .27077

= 13.51773 Ω

= 13.52 Ω

7 0
4 years ago
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3 years ago
The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current
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Answer:

I = 11.26 mA

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given,

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radius = 0.01 × 10⁻² m

resistance = \dfarc{\rho l}{A}

ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C

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During an auto accident, the vehicle’s air bags deploy and slow down the passengers more gently than if they had hit the windshi
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Answer:

d = 0.38 m

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3 years ago
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