2 years ago

The components of a 15 meter per second velocity at an angle of 60 degres above the horizontal

Physics

1 answer:

Neko [114]2 years ago

6 0

X= 7.5 m/s
Y= 12.99 m/s

You might be interested in

As mass increases what happens to the kinetic energy

AnnyKZ [126]

As mass increases kinetic energy also increases; kinetic energy is directly proportional to mass so whatever is done to either affects the other one the same. i hope this helps :)

5 0

3 years ago

What is the relationship between the buildup of electons and the sudden flow of electrons from one charged object to another?

melisa1 [442]

Static electricity

hope this helps :)

5 0

3 years ago

Read 2 more answers

PLEASE HELP!! THIS IS DUE RN!!

Oliga [24]

Answer:

know on car wright now

Explanation:

4 0

2 years ago

What is the final velocity, in meters per second, of a freight train that accelerates at a rate of 0.085 m/s2 for 7.5 min, start

Llana [10]

Answer:

$v_f=41.65\frac{m}{s}$

Explanation:

The final velocity is given by the following kinematic equation:

$v_f=v_0+at$

Here, $v_0$ is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

$7.5min*\frac{60s}{1min}=450s$

Now, we calculate the final velocity:

$v_f=3.4\frac{m}{s}+(0.085\frac{m}{s^2}(450s))\\v_f=41.65\frac{m}{s}$

4 0

3 years ago

A force is applied to a block to move it up a 30° incline. The incline is frictionless, the block is initially at rest, F= 65.0

muminat

Answer:

0.96 m, upward

Explanation:

$\theta=30^{\circ}$

$F=65 N$

$M=5 kg$

Initial velocity, u=0

$t=0.550 s$

$Fcos\theta-Mgsin\theta=Ma$

Where $g=9.8 m/s^2$

Substitute the values

$65cos30-5\times 9.8sin30=5a$

$31.8=5a$

$a=\frac{31.8}{5}=6.36 m/s^2$

$S=ut+\frac{1}{2}at^2$

$S=0+\frac{1}{2}(6.36)(0.55)^2=0.96 m$

Hence,the block moves upward because displacement is positive.

7 0

3 years ago