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kozerog [31]
3 years ago
11

ASE (National Institute for Automotive Service Excellence) certified professionals must be retested every _______ years to keep

up with ever advancing automotive technology. A. three B. four C. five D. two
Physics
1 answer:
Bess [88]3 years ago
4 0
Hi,

The correct answer is C. five 

I hope I helped :)
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You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to
goldenfox [79]

Answer:

f = 1.69*10^5 Hz

Explanation:

In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

V_L=\omega iL=2\pi f i L         (1)

V_L: voltage = 12.0V

i: current  = 2.40mA = 2.40*10^-3 A

L: inductance = 4.70mH = 4.70*10^-3 H

f: frequency = ?

you solve the equation (1) for f and replace the values of the other parameters:

f=\frac{V_L}{2\pi iL}=\frac{12.0V}{2\pi (2.4*10^{-3}A)(4.70*10^{-3}H)}=1.69*10^5Hz      

The frequency of the sinusoidal voltage is f

3 0
3 years ago
Burning a canful of petrol or dropping it. which is likely to release most energy?​
Neporo4naja [7]

Answer:

Burning of canful of petrol will release more energy

Explanation:

If you like my answer than please mark me brainliest

5 0
3 years ago
30 POINTS!
brilliants [131]

Answer:

d

Explanation:

5 0
3 years ago
Read 2 more answers
A flatbed truck is carrying a 20.0 kg crate along a level road. the coefficient of static friction between the crate and the bed
Dahasolnce [82]
<span>3.92 m/s^2 Assuming that the local gravitational acceleration is 9.8 m/s^2, then the maximum acceleration that the truck can have is the coefficient of static friction multiplied by the local gravitational acceleration, so 0.4 * 9.8 m/s^2 = 3.92 m/s^2 If you want the more complicated answer, the normal force that the crate exerts is it's mass times the local gravitational acceleration, so 20.0 kg * 9.8 m/s^2 = 196 kg*m/s^2 = 196 N Multiply by the coefficient of static friction, giving 196 N * 0.4 = 78.4 N So we need to apply 78.4 N of force to start the crate moving. Let's divide by the crate's mass 78.4 N / 20.0 kg = 78.4 kg*m/s^2 / 20.0 kg = 3.92 m/s^2 And you get the same result.</span>
6 0
3 years ago
We see a full moon by reflected sunlight. How much earlier did the light that enters our eye leave the sun? the earth-moon and e
Tju [1.3M]

The time taken by the light reflected from sun to reach on earth will be 8.4 minutes.

To find the answer, we need to know about the distance travelled by light.

<h3>How to find the time taken by the light reflected from sun to reach on earth?</h3>
  • So, in order to solve this problem, we must first know how far the moon is from Earth and how far the Sun is from the moon.
  • These distances are given as 3.8×10^5 km (Earth-Moon) and 1.5×10^8 km (Sun- Earth).
  • Since the Moon and Sun are on opposite sides of Earth during a full moon, the light's distance traveled equals,

         d=(1.5*10^8km)+2(3.8*10^5km)=1.51*10^8km=1.51*10^{11}m

  • As we know that light travels at a speed of 300,000 km per second. then, the time taken by the light reflected from sun to reach on earth will be,

                      t=\frac{1.51*10^{11}}{3*10^8}=503.33 s\\t=\frac{503.33}{60}=8.4min

Thus, the time it takes for the light from the Sun to reach Earth and be recognized as 8.4 minutes.

Learn more about distance here:

brainly.com/question/11495758

#SPJ4

6 0
2 years ago
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