CsH90 + __02 →

A 845 mL NaCl solution is diluted to a volume of 1.19 L and a concentration of 6.00 M . What was the initial concentration? Expr

marysya [2.9K]

The initial concentration was 8.45M

Step 1: Given data

Initial concentration (C₁): ?

Initial volume (V₁): 635 mL = 0.845 L

Final concentration (C₂): 6.00 M

Final volume (V₂): 1.19 L

Step 2: Calculate the initial concentration

We have a concentrated NaCl solution and we want to prepare a diluted one. We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₁ = C₂ × V₂ / V₁

C₁ = 6.00 M × 1.19 L / 0.845 L

C₁ = 8.45 M

Thus, The initial concentration was 8.45M

Learn more about concentration here:

brainly.com/question/10725862

#SPJ4

7 0

2 years ago

6.0 L of gas in a piston at a pressure of 1.0 atm are compressed until the volume is 3.5 L. What is the new pressure inside the

dimulka [17.4K]

From the calculations and by the use of Boyles law, the new pressure of the gas is 1.7 atm

The term gas law is used to demonstrate the relationship between the volume, pressure, number of moles and temperature of a gas.

Using the Boyles law;

P1 = 1 atm

P2 = ?

V1 = 6 L

V2 = 3.5 L

P1V1= P2V2

P2= P1V1/V2

P2= 1 atm * 6 L/3.5 L

= 1.7 atm

Learn more about Boyles law:brainly.com/question/1437490

#SPJ1

3 0

2 years ago

Calculate the volume in liters of a M potassium dichromate solution that contains of potassium dichromate . Round your answer to

maksim [4K]

The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

<u>Answer:</u> The volume of solution is 5.2 L

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

We are given:

Molarity of solution = 0.13 M

Given mass of potassium dichromate = 200. g

Molar mass of potassium dichromate = 294.15 g/mol

Putting values in above equation, we get:

$0.13M=\frac{200}{294.15\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{294.15\times 0.13}=5.23L$

Hence, the volume of solution is 5.2 L

3 0

3 years ago

An atom in the ground state contains 8 valence electrons this atom is classified as a

Alekssandra [29.7K]

Noble Gas. Metals have 1 or 2 Valence Electrons. Halogens have 7 Valence Electrons. Semi-Metals can have different amounts.

5 0

4 years ago

Read 2 more answers

What is the ph of 0.51 m ca(ch3coo)2 solution?

Sidana [21]

Answer : The pH of calcium acetate solution will be 9.38.

Explanation : When calcium acetate dissocates completely in solution to form Calcium(+2) ions and two acetate ions, this gives the acetate ion concentration as (2 X 0.51 M) = 1.02 M

Acetate ion then hydrolyzes as follows;

$C_{2}H_{3}O_{2}^{-} + HOH HC_{2}H_{2}O_{2} + OH^{-}$ :