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ki77a [65]
3 years ago
15

Solve the equation. Then check your solution.

Mathematics
2 answers:
KiRa [710]3 years ago
5 0
Answer: A i hope I’m right I don’t know if I am if not sorry
madreJ [45]3 years ago
4 0

Answer: A

Step-by-step explanation: h + 1.5 = 8.4

Isolate the variable. Subtract 1.5 from both sides of the equation.

h + 1.5 - 1.5 = 8.4 - 1.5

h = 6.9

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I'd really appreciate some help on these questions, I'm really struggling
nikklg [1K]
We can use linear combinations of the equations to eliminate variables.

3x - 4y = 1
-2x + 3y = 1

To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second. 

9x - 12y = 3
-8x + 12y = 4

Adding,
x = 7

We could solve for y directly but let's use another linear combination, twice the first plus three times the second:

2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)

y = 5

Check: 3(7)-4(5)=1 good.   -2(7)+3(5)=1 good.

Q18 Answer: (7,5)

y = -3x + 5
5x - 4y = -3

4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)

5x = -12x + 20 -3

17 x = 17

x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good

Q19 Answer (1,2)

6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good   2y+24=2(-7)+24=10=x good

Q20 Answer (10,-7)


3x + y = 18
-7x + 3y = -10
9x  + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6

Check: 3(4)+6=18 good,  -7(4)+3(6)=-10 good

Q21 Answer: (4,6)

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3 years ago
Which choice gives the solution of this inequality?<br> 3t + 7 &lt; 28
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Answer:7

Step-by-step explanation:

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3 years ago
Caroline spent $42.14 on groceries after using coupons and store discounts. Without the coupons and store discounts, the groceri
mash [69]
The answers is 14%
49 multiply by 14% is 6.86
42.14 + 6.86= 59
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3 years ago
Which statement describes a unit rate?
Artyom0805 [142]

Answer:

C

Step-by-step explanation:

Because it is saying he drove 45 miles per hour.

3 0
3 years ago
Read 2 more answers
2b^2+4b–2=0 what is the answer?
s2008m [1.1K]
2b^2+4b-2=0\\&#10;2(b^2+2b-1)=0\\&#10;2(b^2+2b+1-2)=0\\&#10;2((b+1)^2-2)=0\\&#10;2(b+1)^2-4=0\\\&#10;2(b+1)^2=4\\\&#10;(b+1)^2=2\\&#10;b+1=-\sqrt2 \vee b+1=\sqrt2\\&#10;b=-1-\sqrt2 \vee b=-1+\sqrt2&#10;&#10;
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4 years ago
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