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rusak2 [61]
2 years ago
10

Hello. I was stuck on this. Can you please help? Will give brainliest answer to the best one. Theres no need to go into a big ex

planation, just saying. Will give 5 stars and thanks.

Mathematics
1 answer:
liraira [26]2 years ago
8 0

Answer:

graph C

Step-by-step explanation:

Well I lik it spread out cause you get more information and you can tell how the data is aligned and not scrunched up. Since the example said that the explanatory variable (indepdent variable) is best on the X axis, only C and A are left. A is all scrunch’s up and data could be read worng, but C is nice and spread and it shows all the data and rating clearly

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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Will give brainliest
dmitriy555 [2]

Answer:

<h2><em><u>18</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

Radius of the cylinder = 3cm

Height of the cylinder = 3cm

<em><u>Therefore</u></em><em><u>, </u></em>

Lateral surface area of the cylinder

= 2\pi rh

= 2\pi \times 3 \times 3 {cm}^{2}

= 2\pi \times 9 {cm}^{2}

= 18\pi {cm}^{2}

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>The</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>green</u></em><em><u> </u></em><em><u>box</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>18</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

4 0
3 years ago
Read 2 more answers
Need help with this question ASAP!
kenny6666 [7]

Answer:

(-6, -3)

Step-by-step explanation:

The coordinate is at (2, -1), when using a dilation with a scale factor of 3, multiply the coordinates by 3.

(2, -1) ------> (2 x 3, -1 x 3) ----------> (6, -3)

When reflecting the point over the y-axis, take the opposite of the x coordinate.

(6, -3) ------> (-6, -3)

5 0
2 years ago
Gradient of line AB (3,7) and (5,11)​
larisa [96]

Answer:

Gradient is change in y over change in x.

gradient = y1-y2 ÷ x1-x2

=7-11 ÷ 3-5

=-4 ÷ -2

=2

4 0
3 years ago
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Donal currently has 7,200 points in his fantasy baseball league, which is 20% more points than Scott How many points does Scott
zlopas [31]

Answer:

5760

Step-by-step explanation:

7200-20%=5760

7 0
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