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RUDIKE [14]
3 years ago
11

What are middle-latitude cyclones?

Chemistry
1 answer:
dedylja [7]3 years ago
8 0

your answer is B low-pressure systems that cause stormy weather

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Unrestricted populations of organisms experience _____.
Fudgin [204]
Unrestricted populations of organisms experience Exponential growth. 

As a population reaches is carrying capacity there is an increase in competition for All of the above.
 Hope I helped. 
5 0
2 years ago
Read 2 more answers
How is hydrogen in heavy water different from hydrogen in normal water?
tatyana61 [14]

Answer:

I'd say the correct answer is A

Explanation:

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6 0
2 years ago
Which of the following is an example of qualitative
vichka [17]

Answer:

Option =C each mouse in the study has brown ears.

Explanation:

Qualitative:

Qualitative properties are those that can be only observed but not measured in numerical values. These are observed through senses: touch, sight, smell, taste and hear.

For example:

Color, odor, brittleness, taste etc.

Quantitative:

Quantitative properties can be measured in numerical values.

For example:

Melting point, boiling point, conductivity, viscosity, density, hardness and solubility.

In short we can say that qualitative is a measure of quality while the quantitative is a measure of quantity.

4 0
3 years ago
3. I have 10 moles of a gas mixture. If there are 2.7 moles of hydrogen gas
UkoKoshka [18]

Answer:

there are two moles

Explanation:

6 0
3 years ago
How much heat, in calories, is needed to raise the temperature of 125.0 g of Lead (c lead = 0.130 J/g°C) from 17.5°C to 41.1°C?
pav-90 [236]
95.6 cal
are needed.
Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.
8 0
3 years ago
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