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natita [175]
3 years ago
14

Water exists in liquid form between its 1. Freezing and Boiling point 2. Freezing and melting point 3. Boiling and melting point

4. Sublimation and deposition point
Chemistry
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

Freezing and boiling point

Explanation:

A liquid form of any substance is an intermediate form between the solid form and the gaseous form.

Decreasing the temperature of liquid water according to the phase diagram of H_2O would freeze it and we would have a phase change from liquid to solid (ice) at the freezing point of water.

Similarly, heating water to its boiling point would evaporate water and we would have a phase change from liquid to gas (water vapor).

Therefore, liquid water exists between its freezing and boiling point.

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6. Which group of compounds is described as insoluble?
Sedaia [141]

Answer:phosphates are insoluble in water

Explanation:

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3 years ago
Describe the similarities and differences between herbivores,carnivore,and omnivores​
vredina [299]

Answer:

Herbivores only eat plants . Remember HERBS are PLANTS.

Carnivores only eat meat. Remember CARNE = MEAT in Spanish.

Omnivores eat MEAT & PLANTS.

Explanation:

Differences are what they eat, similarities omnivores eat both.

3 0
3 years ago
How many grams of barium chloride (BaCl2) are there in 0.187 mol?<br> 0.187 mol
igor_vitrenko [27]

Answer:

38.9 grams of BaCl_2

Explanation:

0.187 mol BaCl2 x \frac{208 g}{1 mol}

0.187 m x 208 g/m

0.187 x 208 g

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8 0
3 years ago
The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant
enot [183]

Answer: C=\frac{\pi}{R\times T}

Explanation:-

Osmotic pressure is a colligative property which depends on the amount of solute added.

\pi=CRT

\pi = osmotic pressure = 5.1 atm

C= concentration in Molarity

R= solution constant = 0.0821 Latm/Kmol

T= temperature = 312 K

C=\frac{\pi}{R\times T}

C=\frac{5.1atm}{0.0821Latm/Kmol\times 312K}=0.2mol/L

Thus the equation for calculating the molarity of this solution is C=\frac{\pi}{R\times T}

4 0
3 years ago
How many of grams of CuSO4 are in 475ml of a 2.0M aqueous solution
Anettt [7]

Answer:

151.63 g

Explanation:

We first get the number of moles;

Moles = Molarity × volume

          = 2.0 × 0.475

          = 0.95 moles

1 mole of CuSO4 = 159.609 g/mol

Therefore;

Mass = moles × molar mas

         = 0.95 moles × 159.609 g/mol

         = 151.63 g

8 0
4 years ago
Read 2 more answers
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