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natita [175]
3 years ago
14

Water exists in liquid form between its 1. Freezing and Boiling point 2. Freezing and melting point 3. Boiling and melting point

4. Sublimation and deposition point
Chemistry
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

Freezing and boiling point

Explanation:

A liquid form of any substance is an intermediate form between the solid form and the gaseous form.

Decreasing the temperature of liquid water according to the phase diagram of H_2O would freeze it and we would have a phase change from liquid to solid (ice) at the freezing point of water.

Similarly, heating water to its boiling point would evaporate water and we would have a phase change from liquid to gas (water vapor).

Therefore, liquid water exists between its freezing and boiling point.

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When it is operating properly a chemical plant?
Alexxandr [17]
The operating properly of a chemical plant would have to the same property of any chemicals but its in a plant form instead of test tubes it would have a stem and leaves and you could squeaz the plant and get it out of the plant
4 0
3 years ago
A liquid has a mass of 40.24g and a volume of 50.0mL. What is its density?
Musya8 [376]
P=m/V

m=40.24 g
V=50.0 mL=50.0 cm³

p=40.24/50.0=0.8048 g/cm³
7 0
4 years ago
Arrange the following aqueous solutions, all at 25 ∘C, in order of decreasing acidity. 1 = most acidic; 4 = least acidic Rank fr
Akimi4 [234]

Answer:

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Explanation:

Hello,

In this case, such order could be computed by means of the pH, the lower the pH the more acid the solution, thus:

1. 0.0018 M OH-:

pOH=-log(0.018)=1.744\\pH=14-pOH=12.2

2. 0.023 M H3O+

pH=-log(0.023)=1.64

3. pH=9.45

4.

pH=14-5.52=8.48

Therefore the order is

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Best regards.

5 0
3 years ago
A gas sample has an original volume of 760 ml when collected at 700 mm and 40oC. If a change is made in the gas temperature whic
alexandr1967 [171]

Answer:

235k

Explanation:

To solve this problem, we will use the general gas equation.

In its simplest form, the general gas equation can be represented as follows:

P1V1/T1 = P2V2/T2

P1 = 700mmHg

V1 = 760ml

T1 = 40 degrees Celsius = 40 + 273.15 = 313.15K ( conversion into standard temperature unit)

P2 = 1.25 atm

We have to covert this into the same unit as the first pressure.

760mmHg = 1atm

x mmHg = 1.25 atm

x = 1.25 * 760 = 950mmHg

V2 = 420ml

T2 = ?

Now, rearranging the equation will yield:

T2 = P2V2T1/P1V1

T2 = 950 * 420 * 313.5/700 * 760

T2 = 235.125K or -38.025 degrees celcius

6 0
3 years ago
At which stage of the thunderstorm can you except it to begin to die down
salantis [7]

C. The dissipation stage

3 0
3 years ago
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