Answer:
34.9 mL
Explanation:
First we <u>convert 23.6 g of LiBr into moles</u>, using its <em>molar mass </em>(86.845 g/mol):
- 23.6 g ÷ 86.845 g/mol = 0.272 mol LiBr
Now we can <u>calculate the required volume</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- liters = moles / Molarity
- 0.272 mol / 7.8 M = 0.0349 L
We can <u>convert L into mL</u>:
- 0.0348 L * 1000 = 34.9 mL
Answer:
Explanation:
We are given that
Stress,
Temperature,
Stress,
Modulus of elasticity=
We have to find the temperature must the wire be heated.
Using the formula
Answer:
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Answer:
B
Explanation:
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Answer:
0.00579 M
Explanation:
Concentration of acid CA= 0.0338 M
Volume of acid VA= 12.0mL
Concentration of base CB= ??????
Volume of base VB= 35.00mL
Now we must write the equation of the reaction:
Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)
We can now write the number of moles of acid and base
Number of moles of acid NA= 2
Number of moles of base NB= 1
From:
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CB= CA VA NB/ VB NA
CB=0.0338 × 12.0 × 1/ 35.0 × 2
CB= 0.00579 M