When balancing the equation you need to know how many moles reacted and how many were formed.To balance this equation we require 1 moles of C2H4, 3moles of O2 to form 2 moles CO2 and 2 moles H2o
therefore the equation is represented as
C2H4+3O2 ->2CO2+2H2O
Answer:
61%
Explanation:
Cd2+ and CD(OH)2 both contain the Cd2+ specie which is chemically similar to Zn2+both being in the same group in the periodic table. Cd2+ is know to be toxic when absorbed together with Zn 2+ ions and will definitely be toxic to the aquatic species.
Answer : C
Reason : The product is MgO which is Magnesium Oxide + CO2 which is carbon dioxide because of the 2
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Robert Hooke deterred that all animals were made of cells
