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natita [175]
3 years ago
10

What is the concentration of a calcium hydroxide solution, if 35.00 mL of the base is completely neutralized by 12.0 mL of 0.033

8 M HCl?
Chemistry
1 answer:
Papessa [141]3 years ago
5 0

Answer:

0.00579 M

Explanation:

Concentration of acid CA= 0.0338 M

Volume of acid VA= 12.0mL

Concentration of base CB= ??????

Volume of base VB= 35.00mL

Now we must write the equation of the reaction:

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

We can now write the number of moles of acid and base

Number of moles of acid NA= 2

Number of moles of base NB= 1

From:

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CA VA NB/ VB NA

CB=0.0338 × 12.0 × 1/ 35.0 × 2

CB= 0.00579 M

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A mole of X reacts at a constant pressure of 43.0 atm via the reaction X(g)+4Y(g)→2Z(g), ΔH∘=−75.0 kJ Before the reaction, the v
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