Answer:
B. It has mass
Explanation:
The Newtons Universal gravitacion law is : F = G.
, where <u>F</u> is the force exerted , <u>m1</u> and <u>m2</u> are the earth's mass and the object's mass, <u>d</u> is the distance and <u>G</u> the gravitacional constant. Comparing to the options we can say that the Earth exerts a gravitational force on objects on its surface because of its mass.
The first one is right switch the second and third one and keep the last one and that should be right
Answer:
The stress is 
Explanation:
From the question we are told that
The diameter of the post is 
The length is 
The weight of the loading mass
Generally the radius of the post is mathematically represented as
=> 
Generally the area of the post is
=> 
=> 
Generally the weight exerted by the load is mathematically represented as
=> 
=> 
Generally the stress is mathematically represented as
=> 
=>
Answer:
d sin tea = m λ
Explanation:
When we have a two-slit system, the optical path difference determines whether the intensity reaching an observation screen is maximum or zero.
To find this difference in optical path, we assume that the screen is much farther than the gap is, we draw a perpendicular from ray 1 to the second ray
OP = d sin θ
now to have constructive interference and see a bright line this leg must be an integer number of wavelengths, ose
d sin tea = m λ
where
d is the distance between the two slits
θ complexion the angle sea the point hold it between the two slits
λ the wavelength of the coherent light used
m an integer, which counts the number of lines of interference
Units in the SI system
d, lam in meters
θ degrees
m an integer
Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
