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raketka [301]
3 years ago
12

The stored chemical energy in fuels is MOST OFTEN converted to _________ and _________ energy through combustion.

Physics
1 answer:
Vlad1618 [11]3 years ago
6 0
I believe is c) light and electrical
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A ball is thrown at an angle of to the ground. If the ball lands 90 m away, what was the initial speed of the ball?
andre [41]

Answer:

The initial speed of the ball is 30 m/s.

Explanation:

It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :

R=\dfrac{u^2\ sin2\theta}{g}

u is the initial speed of the ball.

v=\sqrt{\dfrac{Rg}{sin2\theta}}

v=\sqrt{\dfrac{90\times 9.8}{sin2(45)}}

v = 29.69 m/s

or

v = 30 m/s

So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.                                      

8 0
3 years ago
Why is it important to use constants in an experiment?
Firlakuza [10]
<span>In order for the results to be valid, the dependent variable can only be affected by the independent variable, so somethings need to be kept constant. The things that need to be kept constant are called  controlled variables.</span>
5 0
3 years ago
If you remove large amounts of heat from a liquid, what could happen
snow_lady [41]
A liquid becomes a solid when energy is removed. The energy content decreases, and the speed of the particles decrease.
3 0
3 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
In a solution, the solvent is present in the larger amount. <br> A True <br> B False
lana [24]
Th statement represented above : In a solution, the solvent is present in the larger amount is definitely FALSE. I choose this answer as a correct one as it also could be a solutions of alcohol ot for example <span>walter which means it's not so solid and liquid respectively. Hope it's clear! Regards!</span>
8 0
3 years ago
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