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leonid [27]
3 years ago
12

Does the second picture answer the first one, if not what am i missing, I’m incredibly confused.

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0
Answer:

Yes

Explanation:

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Please please help
il63 [147K]

Explanation:

question 44

the number 35 of bromine represents the atomic number

question 45

29 protons,

27 electrons

29-27 = +2

the charge on the following particle is

+2

4 0
3 years ago
Water changes from a liquid to a gas in the process of evaporation. <br> true or false
Umnica [9.8K]
This it true because in the triangle of the transformation from solid, liquid, and gas
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3 years ago
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When Lithium-7 loses 1 electron it
IrinaK [193]

If it loses an electron, it will become an ion.

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2 years ago
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Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
When methane is burned with oxygen, the products are carbon dioxide and water, If you produce 20 grams of water and 10 grams of
scZoUnD [109]
When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? First you need to write a balanced chemical equation.
3 0
3 years ago
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