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ira [324]
3 years ago
8

Sam is riding his bike and spots a sinkhole. He slows his bike from 14.0 m/s to 2.0 m/s on 6.0 seconds. What is the bikes negati

ve acceleration?
Physics
2 answers:
Paul [167]3 years ago
7 0
The bikes negative acceleration is -2(m/s^2)
VARVARA [1.3K]3 years ago
4 0
By definition, average acceleration will be:
a=(v(f)-v(i))/t
a=(2-14)/6=-2 (m/s^2)
________
-2(m/s^2)
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a 4kg block is attatched to a vertical sspring constant 800n/m. the spring stretches 5cm down. how much elastic potential energy
kow [346]

The Potential energy stored in the system is 1 J

<u>Explanation:</u>

Given-

Mass, m = 4 kg

Spring constant, k = 800 N/m

Distance, x = 5cm = 0.05m

Potential energy, U = ?

We know,

Change in potential energy is equal to the work done.

So,

U = \frac{1}{2} k (x)^2\\\\

By plugging in the values we get,

U = \frac{1}{2} * 800 * (0.05)^2\\ \\U = 400 * 0.0025\\\\U = 1J\\

Therefore, Potential energy stored in the system is 1 J

8 0
3 years ago
The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

6 0
3 years ago
The measured value of the speed of light is about 300,000 km/s. suppose a futuristic space train is traveling at 200,000 km/s wi
Gwar [14]
The speed of light generally would be 300000km/s but since the train is moving in the same direction as the light it would apparently appear to be 100000km/s
3 0
3 years ago
Why do you suffer more pain than me when I slap your face?​
alex41 [277]
This because your face has more sensitive tissue than anywhere else in your body

Hope this helps
5 0
3 years ago
In an experiment in space, one proton is held fixed and another proton is released from rest a distance of 1.00 mm away. part a
mihalych1998 [28]
<span>We can use Coulomb's law to find the force F acting on the proton that is released. F = k x Q1 x Q2 / r^2 k = 9 x 10^9 Q1 is the charge on one proton which is 1.6 x 10^{-19} C Q2 is the same charge on the other proton r is the distance between the protons F = (9x10^9) x (1.6 x 10^{-19} C) x (1.6 x 10^{-19} C) / (10^{-3})^2 F = 2.304 x 10^{-22} N We can use the force to find the acceleration. F = ma a = F / m a = (2.304 x 10^{-22} N) / (1.67 x 10^{-27} kg) a = 1.38 x 10^5 m/s^2 The initial acceleration of the proton is 1.38 x 10^5 m/s^2</span>
8 0
3 years ago
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